Question

During a school tournament, Team A had 10 of its 12 team members present.

Answer 1

Answer:

Team A.

Step-by-step explanation:

We know that Team A had 10 of its 12 members present.

We can write this as the following fraction:

$A=10/12$

We can convert this to a decimal by dividing the two numbers. Use a calculator:

$A\approx.8333$

And we can convert this to a percent by moving the decimal too places to the right and by adding a percent sign:

$A\approx83.33\%$

So, about 83.33% of members on Team A was present.

We know that Team B had 13 of its 15 members present.

We can write this as the following fraction:

$B=13/15$

Again, we can convert this to a decimal by dividing the two numbers:

$B\approx 0.8667$

Change this to a percent:

$B\approx86.67\%$

So, Team A had a participation rate of 83.33% while Team B had a participation rate of 86.67%.

So, the team that had the lesser percent of the team present at the tournament is Team A.

And we're done!