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bonufazy [111]
3 years ago
11

If f(x) = one/nine x -2, what is f^-1(x)

Mathematics
1 answer:
astraxan [27]3 years ago
6 0

Answer:

f^{-1} (x)=9x+18

Step-by-step explanation:

Assuming f(x)=\frac{1}{9} x-2

What we have to do is replace f(x) with y, swap the locations of x and y, and then solve for y.

y= \frac{1}{9} x-2\\\\x=\frac{1}{9}y-2\\ \\x+2=\frac{1}{9}y\\\\y=9x+18\\\\f^{-1} (x)=9x+18

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