If f(x) = one/nine x -2, what is f^-1(x)

Mathematics

1 answer:

astraxan [27]3 years ago

6 0

Answer:

$f^{-1} (x)=9x+18$

Step-by-step explanation:

Assuming $f(x)=\frac{1}{9} x-2$

What we have to do is replace f(x) with y, swap the locations of x and y, and then solve for y.

$y= \frac{1}{9} x-2\\\\x=\frac{1}{9}y-2\\ \\x+2=\frac{1}{9}y\\\\y=9x+18\\\\f^{-1} (x)=9x+18$

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