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liraira [26]
3 years ago
11

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = (x – 1). What is the slope-i

ntercept form of the equation for this line?
y =1/2 x + 2
y = 1/2x – 4
y = 1/2x + 5/2
y = 1/2x – 7/2
Mathematics
2 answers:
bulgar [2K]3 years ago
8 0
(-9,-2) (1,3)
slope = (3 - (-2) / (1 - (-9) = 5/10 = 1/2

y - y1 = m(x - x1)
slope(m) = 1/2
(1,3)...x1 = 1 and y1 = 3
sub
y - 3 = 1/2(x - 1)
y - 3 = 1/2x - 1/2
y = 1/2x - 1/2 + 3
y = 1/2x - 1/2 + 6/2
y = 1/2x + 5/2 <=== slope intercept form
Effectus [21]3 years ago
4 0

Answer: y=\dfrac{1}{2}x+\dfrac{5}{2}

Step-by-step explanation:

Equation of a line passing through points (a,b) and (c,d) is given by :-

(y-b)=\dfrac{d-b}{c-a}(x-a)

Similarly, the equation of line passing through (-9, -2) and (1, 3) is given by :-

(y-3)=\dfrac{3-(-2)}{1-(-9)}(x-1)

(y-3)=\dfrac{3+2}{1+9)}(x-1)

(y-3)=\dfrac{5}{10}(x-1)

(y-3)=\dfrac{1}{2}(x-1)

(y-3)=\dfrac{1}{2}x-\dfrac{1}{2}

Add 3 both sides , we get

y=\dfrac{1}{2}x-\dfrac{1}{2}+3

y=\dfrac{1}{2}x+\dfrac{(2)(3)-1}{2}

y=\dfrac{1}{2}x+\dfrac{5}{2}

Hence, he slope-intercept form of the equation for this line :

y=\dfrac{1}{2}x+\dfrac{5}{2}

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