All categories

3 years ago

Please help me

Mathematics

1 answer:

Kruka [31]3 years ago

6 0

y = x^2 -4x

x = -1

y = (-1)^2 - 4×-1=1+4 = 5

x= 0

y = (0)^2 - 4×0 = 0

x = 1

y = 1^2 -4×1 = 1-4 = -3

x = 2

y = 2^2 -4×2 = 4-8 = -4

x=3

y = 3^2 - 4×3 = 9-12 = -3

x = 4

y = 4^2 - 4×4 = 16 - 16 = 0

now 2nd equation

y = 2x^2 + x

x = -2

y = 2 (-2)^2 + (-2)= 8-2 = 6

x = -1

y = 2 (-1)^2+(-1)= 2-1 = 1

x = 0

y = 2(0)^2 +0 = 0

x = 1

y = 2 (1)^2 + 1 = 3

x = 2

y = 2(2)^2+2= 8 + 2 = 10

You might be interested in

Is the relationship shown by the data linear? If so, model the data with an equation. x y –7 5 –5 9 –3 13 –1 17

diamong [38]

Given:

The table of values is:

x : -7 -5 -3 -1

y : 5 9 13 17

To find:

Whether the given data is linear and then find the equation.

Solution:

The given data is linear if the slope and rate of change is constant.

Slope formula:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Using the slope formula. we get

$\dfrac{9-5}{-5-(-7)}=2$

$\dfrac{13-9}{-3-(-5)}=2$

$\dfrac{17-13}{-1-(-3)}=2$

Since the rate of change is constant, i.e., 2, therefore the given data is linear.

The slope of a linear equation is 2 and it passes through the point (-7,5). So, the equation of the line is:

$y-y_1=m(x-x_1)$

$y-5=2(x-(-7))$

$y-5=2(x+7)$

$y-5=2x+14$

Adding 5 on both sides, we get

$y-5+5=2x+14+5$

$y=2x+19$

Therefore, the equation for the given data is $y=2x+19$ .

8 0

3 years ago

Debby new puppy weighed 10 1/8 pounds. After a month it had gained 6 1/3 pounds. What is the weight of the puppy after a month?

tatuchka [14]

The puppy after a month would weigh 16 11/24

I hope this helps

Have a happy holidays:)

7 0

3 years ago

1/4 + 1/4 + 3/4 + 3/4 equals

juin [17]

Answer:the answer is 2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write 64,500 in scientific notation

lukranit [14]

6.45 x 10 to the 4th.

5 0

3 years ago

What is the coordinate?

faltersainse [42]

Remember that the equation of a circle is:
$(x - h)^{2} + (y - k)^{2} = r^{2}$
Where (h, k) is the center and r is the radius.
We need to get the equation into that form, and find k.

$x^{2} - 6x + y^{2} - 10y = 56$

Complete the square. We must do this for x² - 6x and y² - 10y separately.

x² - 6x
Divide -6 by 2 to get -3.
Square -3 to get 9. Add 9,
x² - 6x + 9

Because we've added 9 on one side of the equation, we have to remember to do the same on the other side.

$x^{2} - 6x + 9 + y^{2} - 10y = 65$

Now factor x² - 6x + 9 to get (x - 3)² and do the same thing with y² - 10y.

y² - 10y
Divide -10 by 2 to get -5.
Square -5 to get 25.
Add 25 on both sides.

$(x - 3)^{2}+ y^{2} - 10y + 25= 90$

Factor y² - 10y + 25 to get (y - 5)²

$(x - 3)^{2}+ (y - 5)^{2} = 90$

Now our equation is in the correct form. We can easily see that h is 3 and k is 5. (not negative because the original equation has -h and -k so you must multiply -1 to it)

Since (h, k) represents the center, (3, 5) is the center and 5 is the y-coordinate of the center.

7 0

3 years ago