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prohojiy [21]
3 years ago
15

Please help me

Mathematics
1 answer:
Kruka [31]3 years ago
6 0

y = x^2 -4x

x = -1

y = (-1)^2 - 4×-1=1+4 = 5

x= 0

y = (0)^2 - 4×0 = 0

x = 1

y = 1^2 -4×1 = 1-4 = -3

x = 2

y = 2^2 -4×2 = 4-8 = -4

x=3

y = 3^2 - 4×3 = 9-12 = -3

x = 4

y = 4^2 - 4×4 = 16 - 16 = 0

now 2nd equation

y = 2x^2 + x

x = -2

y = 2 (-2)^2 + (-2)= 8-2 = 6

x = -1

y = 2 (-1)^2+(-1)= 2-1 = 1

x = 0

y = 2(0)^2 +0 = 0

x = 1

y = 2 (1)^2 + 1 = 3

x = 2

y = 2(2)^2+2= 8 + 2 = 10

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Help me please <br> !!!!!!!!!!!!
Tpy6a [65]

Answer:

40

Step-by-step explanation:

Angle Formed by Tangent and Secant = 1/2 (DIFFERENCE of Intercepted Arcs)

< WVT = 1/2 ( WT - UW)

3x+4    = 1/2 (( 14x +7) - (7x+11))

Distribute

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Combine like terms

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