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lubasha [3.4K]
3 years ago
7

Five chips numbered 1 through 5 are placed in a bag. A chip is drawn and replaced. Then a second chip is drawn. Find the probabi

lity that one chip is even AND the other is odd. (Hint: You can choose an even chip and then an odd chip, or an odd chip and then an even chip.)
Mathematics
1 answer:
Vesna [10]3 years ago
6 0

12345

The odds of drawing an even chip are \frac{2}{5}.

The odds of drawing an odd chip are \frac{3}{5}.

You multiply the two \frac{2}{5} x  \frac{3}{5} =  \frac{6}{25}.

Knowing you cannot simplify 6/25 any further, you now have your answer!


Hope this helps! <3

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Please answer with clear instructions so that i can apply this to other questions.
kvv77 [185]

Answer:

10 terms

Step-by-step explanation:

equate the sum formula to 55 and solve for n

\frac{1}{2} n(n + 1) = 55 ( multiply both sides by 2 to clear the fraction )

n(n + 1) = 110 ← distribute parenthesis on left side

n² + n = 110 ( subtract 110 from both sides )

n² + n - 110 = 0 ← in standard form

Consider the factors of the constant term (- 110) which sum to give the coefficient of the n- term (+ 1)

the factors are + 11 and - 10 , since

11 × - 10 = - 110 and 11 - 10 = + 1 , then

(n + 11)(n - 10) = 0 ← in factored form

equate each factor to zero and solve for n

n + 11 = 0 ⇒ n = - 11

n - 10 = 0 ⇒ n = 10

However, n > 0 , then n = 10

number of terms which sum to 55 is 10

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Step-by-step explanation:

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