Answer:
22.38 g of silicone-32 will be present in 300 years.
Step-by-step explanation:
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by
where,
= quantity of the substance remaining
= initial quantity of the substance
= time elapsed
= half life of the substance
From the information given we know:
- The initial quantity of silicone-32 is 30 g.
- The time elapsed is 300 years.
- The half life of silicone-32 is 710 years.
So, to find the quantity of silicone-32 remaining we apply the above equation
22.38 g of silicone-32 will be present in 300 years.
Answer:
see explanation
Step-by-step explanation:
1
The cosine function in standard form is
y = acos(bx + c)
where a is the amplitude, period = 
and
phase shift = - 
here b = 2 and c = 
, thus
phase shift = - 
= - 
2
the amplitude = | a |
which has a maximum of a and a minimum of - a
y = 4cosx ← has a maximum value of 4
Consecutive integers are 1 aparrt
they are
x,x+1,x+2,x+3
the 2nd and 4th sum is x+1 and x+3
sum is 34
x+1+x+3=34
2x+4=34
minus 4
2x=30
divide 2
x=15
x+1=16
x+2=17
x+3=18
the numbers are 15,16,17,18
Since I don't see attachment, I guess the solution will be as follows:
1 & 3/4 , since 1 = 4/4, then it could be rewritten :
4/4 & 3/4, hence between these 2 fraction there is 2/4 or 1/2.
The first one is X = 24 & the second one is x= 20
