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3 years ago

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Mari has a part time job. She earns $7 an hour. She makes at most $143.50 a week. What is the greatest number of hours that she

worked

1 answer:

Readme [11.4K]3 years ago

8 0

591.928571 is your answer

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The drug store is having a sale where all merchandise is 1/4 off. A woman buys $30 of merchandise at a sale price. What would sh

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$30 = 75%, so divide it by three and you got your 25%, which ia $10.
$10 * 4 = $40.

So the answer is $40.

Hope this helps.

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3 years ago

Finding missing angles in triangles worksheet answers house

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Step-by-step explanation:

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2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

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Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9

ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

$PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})$

Where:

$\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}$

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

$\frac{5.9}{100}=0.059$

Now we substitute the values:

$PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})$

Now we solve the operations, we get:

$PV_{\text{ord}}=39462.50$

Therefore, the present value must be $39462.50

8 0

1 year ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20%2B1%20%3D%20%5Csqrt%7B3%7D%20" id="TexFormula1" title=" \frac{x}{2

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I hope this helps you

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3 years ago