Set 500 to sum of distances traveled by both cars.
A + c = 824 represents number of tickets to sell
20a + 12c = 13,344 represents cost of each type of ticket
multiply equation 1 by -12 to cancel the variable 'c' and solve for 'a'
-12(a + c = 824)
-12a - 12c = - 9888
20a + 12c = 13,344 add equations together
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8a = 3456 divide both sides by 8
a = 432
To find children's tickets substitute adult numbers back into equation 1.
a + c = 824
432 + c = 824
subtract 432 from both sides
c = 392
adult 432, children 392
Answer:
Step-by-step explanation:
you can round the numbers
27/3= 9
27.36 rounds down to 27 and 3.14 rounds to 3
Answer: 2/3 hours
Step-by-step explanation:
okay so the speed now is 850, which is 850/340 = 2.5 times the original speed
Since It's 2.5 times the original speed,
2.5x = 5/3
so x = 5/3/2.5 = 2/3
