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Mice21 [21]
3 years ago
13

(Picture included) can someone help me with 6 or 7?

Mathematics
1 answer:
lakkis [162]3 years ago
7 0

2x^2+11x-15 Is the answer to 7

Step-by-step explanation:

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EMERGENCY (NEED HEP NOW!!!)
diamong [38]

Answer:

x=-2.25,y=-2.25

Step-by-step explanation:

The given system is

4x - y =  - 9 \\ 3x - 3y = 0

We want to solve the system for x and y that makes the system true.

Let us multiply the first equation by 3 while maintaining the second equation:

12x -3 y =  - 27 \\ 3x - 3y = 0

Subtract the current second equation from the first one.

12x =  - 27

Divide through by 12:

x =  -  \frac{27}{12}  =  - 2.25

From the second equation we have:

3x = 3y

This implies that:

x = y =  - 2.25

8 0
4 years ago
Pls help<br><br> Multiply. write the result in scientific notation<br><br> (1.7*10^-4)(5*10^-5)
kramer
Do the exponents first. 10 to the -4 is 1/10000 or 0.0001 and 10^ -5 is 0.00001. You end up with (1.7*0.0001)(5*0.00001) which is 0.00017*0.00005 which is 0.0000000085 or 0.085*10^-8
5 0
3 years ago
A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

           x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

4 0
3 years ago
Please Help ASAP!!
Brilliant_brown [7]

Answer:

The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.

Step-by-step explanation:

In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't.  Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype.  However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.  

4 0
4 years ago
Need help figuring this one out
Dennis_Churaev [7]

Answer:

4.426020408 × 10∧19

Step-by-step explanation:

First, I found what 540 multiplied by 0.0000000028 was. Next, I took 66921428571428.6 and divided it by the product I got on top.

7 0
3 years ago
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