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Mice21 [21]
2 years ago
13

(Picture included) can someone help me with 6 or 7?

Mathematics
1 answer:
lakkis [162]2 years ago
7 0

2x^2+11x-15 Is the answer to 7

Step-by-step explanation:

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Graph the inequality y>2/3x-1
xenn [34]

Answer:

graph{y>2/3x-1 [-10, 10, -5, 5]}

Explanation:

First, graph a line with the equation y=23x−1. This equation is in the form y=mx+b. 23 is the slope and −1 is the y-intercept.

graph{2/3x-1 [-10, 10, -5, 5]}

However, we are graphing an inequality so we're gonna have to shade either the area above the line or below the line. First, let's look at the inequality symbols.

> Greater than

< Less than

≥ Greater than or equal to

≤ Less than or equal to

If the inequality includes equal to, then the line will be solid. If not, then the line will be dotted. Since the inequality y>23x−1 doesn't contain the equal to, the line will be dotted.

The direction of the inequality sign matters too. If it's greater than, then the top area will be shaded. If it's less than, then the bottom area will be shaded. Since the inequality y>23x−1 has greater than, the top area will be shaded.

graph{y>2/3x-1 [-10, 10, -5, 5]}

5 0
2 years ago
Which congruence rule is the triangle.<br> ex. SSS, SAS, ASA, etc
Basile [38]
Jsjjejn dnjkje. Joke. Che s subs e
3 0
2 years ago
What is the area of a sector with a central angle of 255 and a radius of 18.4 m?
Igoryamba

Answer:

The answer is 753.01 m².

Step-by-step explanation:

Given that the formula of sector is θ/360×π×r² where r represents radius of circle. Then, you have to substitute the values into the formula :

area =  \frac{θ}{360}  \times \pi \times  {r}^{2}

Let θ = 255°

Let π = 3.14,

Let r = 18.4m,

area =  \frac{255}{360}  \times 3.14 \times  {18.4}^{2}

area = 753.01 {m}^{2}  \: (near.hundredth)

5 0
2 years ago
What is the solution to this system of equations? 3x + y= 17 X + 2 y = 49 СА. It has no solution. OB. It has infinite solutions,
hammer [34]

Answer:

do you have a pic

Step-by-step explanation:

5 0
2 years ago
R --&gt; 2 P. Initially you start off with 0.5 M reactants and let the reaction run to equilibrium and calculate the equilibrium
Anit [1.1K]

Answer:

K still the same value

Step-by-step explanation:

given a reaction aA+bB<->cC+dD the constant K is defined as:

\frac{C^{c}D^{d}  }{A^{a}B^{b} }

K is a constant so it won't change the value. Instead, the values of C and D are going to change.  The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.

8 0
2 years ago
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