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lora16 [44]
4 years ago
8

Helppp 8th grade algebra C. Six units left D.six units right

Mathematics
1 answer:
yanalaym [24]4 years ago
5 0
D, six units to the right. This is the answer because the pre-image is six to the left of the newest image. Just count the spaces away!

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Michelle brought an apple cut in 4 for $0.10 per piece. How much should she pay for 3 dozen pieces ​
Leya [2.2K]

Answer:

$0.90

Step-by-step explanation:

\frac{4}{10}=0.4

3 dozen = 36

\frac{36}{0.4} =\frac{y}{0.1}

0.4 × y = 36 × 0.1

0.4y = 3.6

0.4y ÷ 0.4 = 3.6 ÷ 0.4

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5 0
3 years ago
Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you
dalvyx [7]

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

3 0
3 years ago
M
Inessa05 [86]
Need to see the picture ..?
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3 years ago
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