Three friends are sharing equally 3/4 of a pizza. Each person receives 1/4 of the pizza.

When Vivian was born, her grandparents decided to help save for her college education. They put $2000 in an account that pays 1.

melomori [17]

Answer:

P = 2000 * (1.00325)^(t*4)

(With t in years)

Step-by-step explanation:

The formula that can be used to calculated a compounded interest is:

P = Po * (1 + r/n) ^ (t*n)

Where P is the final value after t years, Po is the inicial value (Po = 2000), r is the annual interest (r = 1.3% = 0.013) and n is a value adjusted with the compound rate (in this case, it is compounded quarterly, so n = 4)

Then, we can write the equation:

P = 2000 * (1 + 0.013/4)^(t*4)

P = 2000 * (1.00325)^(t*4)

4 0

2 years ago

Madelyn has x nickels and y dimes, having a maximum of 15 coins worth no

aliina [53]

9514 1404 393

Answer:

2 nickels, 9 dimes

Step-by-step explanation:

When there are a number of overlapping shaded areas on the graph, I find it convenient to use the reverse of the inequalities. That makes the <em>unshaded</em> area the solution space. Here, the vertices of the triangular solution space are ...

(2, 9), (2, 13), (6, 9)

Any of the grid points within (or on) this triangle is a possible solution. One of them is (2, 9) corresponding to 2 nickels and 9 dimes.

__

Three solutions are shown:

(x, y) = (2, 9), (3, 10), (4, 11)

4 0

2 years ago

(m 5/6) (m1/6) ^7 = m^x

nadezda [96]

Answer:

x = 2

Step-by-step explanation:

Here, we want to find the value of x

(m^5/6)(m^1/6)^7 = m^x

= (m^5/6)(m^7/6) = m^x

Using the law of indices for power multiplication

m^(5/6 + 7/6) = m^x

m^(12/6) = m^x

m^2 = m^x

we simply equate the powers in this case since the base are equal

Thus we have

x = 2

3 0

2 years ago

lia gets paid $450 a week pluse commission on het sale. she hopes to earn at least $600 each week. write an inequality to repres

FrozenT [24]

So commission will be $150 450+_=600

3 0

3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

2 years ago