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kati45 [8]
3 years ago
15

Which of the following is the mark of a math novice as compared with a math expert?

Mathematics
2 answers:
malfutka [58]3 years ago
4 0
The answer for this question is choice c. Memorization is not a good way to truly understand math. You want to understand the reasoning behind your answers always.

A math expert is what you should strive to be! The first two choices are great ways to become this.
Dima020 [189]3 years ago
3 0

Answer:

The correct answer is C.

Step-by-step explanation:

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Given: Circle A externally tangent to Circle B.
Zolol [24]
<h2>Answer:</h2>

B. 3

<h2>Step-by-step explanation:</h2>

A tangent is a line that passes through exactly one point on a circle. For any point on a circle, the radius and tangent line through that point are always perpendicular to each other making a right angle. If two triangles touch each other externally, then there will be 3 lines making right angle with radius of the circles at the point of intersection of circle and tangents. These three tangent lines are shown below. They are the black, blue and green ones.

7 0
3 years ago
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What is the simplified form of this expression?
Alexxx [7]

Answer:

Option 4

Step-by-step explanation:

=> -3x^2+2x-4 + 4x^2+5x+9

Combining like terms

=> -3x^2+4x^2+2x+5x-4+9

=> x^2+7x+5

5 0
3 years ago
Hazel has band practice every other day and volunteers every seven days. if she had a band practice and volunteered on oct 23, w
LuckyWell [14K]
Cjdfb hjkbftbbui yuftg
3 0
3 years ago
#2 only <br> And it's to confusing
ipn [44]
They are easy to compare if they all have the same common denominator, then you can easily order them by the magnitude of the numerators...

85/10, -67/10, -56/10, 82/10  so now they are easy to compare...so

-6.7, -28/5, 8.2, 17/2
5 0
3 years ago
Please solve this sheet.
lyudmila [28]
Hello,

A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)

y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1

eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1

Answer :A--> R,K

B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10

answer B--> I,≈W if it is written -1/2*x²  (square has been forgotten)

C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J

D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L

E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!

y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.

y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]




6 0
3 years ago
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