Answer:
See Explanation
Step-by-step explanation:
Given

Required
Determine the number of cans for the wall
The dimension of the wall is not given. So, I will use the following assumed values:


First, calculate the area of the wall



If 
Then 
Cross Multiply:



Make x the subject


400 cans using the assume dimensions.
So, all you need to to is, get the original values and follow the same steps
If we begin with the first term, 2, mult. it by 4 and then subtract 3, we get 5 (not 4, as shown).
If we begin with 4, mult. it by 4 and then subtract 3, we get 13. This agrees with the terms of the given sequence.
If we begin with 13, mult. it by 4 and then subtract 3, we get 49. This agrees with the terms of the given sequence.
Remove the first term, 2, and then the remaining terms follow the given procedure for finding terms.
Answer:
20
Step-by-step explanation:
Simplify both sides of the equation.
−4=
r
20
−5
−4=
1
/20
r+−5
−4=
1
/20
r−5
Flip the equation.
1
/20
r−5=−4
Add 5 to both sides.
1
/20
r−5+5=−4+5
1
/20
r=1
Multiply both sides by 20.
20*(
1
/20
r)=(20)*(1)
r=20
(2^8 . 5^-5 . 19^0)^-2
using PEMDAS
this = (2^8 * 1/5^5 * 1)^-2
= (5^5 / 2^8)^2
= 5^10 / 2^16