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3 years ago

100 points !!!!!!!!!!!!! please help

Mathematics

2 answers:

Hitman42 [59]3 years ago

7 0

$\boxed{\large{\bold{\blue{ANSWER~:) }}}}$

we have to write a word problem for this equation

$\frac{2}{3}*5$

word problems:-

if 1 people needs 2/3 work.So how much work will need to 5 people.??

m_a_m_a [10]3 years ago

5 0

We have to,

write a word problem for this equation,

→ 2/3 × 5

Let's write a word problem,

For one student 2/3 part of one cake is needed. Then how many cakes will they have to buy for 5 students?

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Grapes cost $2.70 per pound. You buy 2.5 pounds of grapes and give the cashier $10. How much change do you receive

allochka39001 [22]

Answer:

$3.25

Step-by-step explanation:

The grapes costs $2.70 per pound but you're buying 2.5 pounds so take $2.70 x 2.5 = $6.75. Now u just take $10 - $6.75 which equals $3.25 and thats ur answer.

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3 years ago

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The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

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3 years ago

What is the total amount in an investment of $3500 that was compounded quarterly for 8 years at a rate of 5%?

erica [24]

Answer:

Principal = 3500

Time = 8 years

We are given that compound quarterly

So, No. of compounds per year = 2

Rate of interest = 5%

Formula : $A=P(1+\frac{r}{n})^{nt}$

Substitute the values :

$A=3500(1+\frac{0.05}{2})^{2 \times 2}$

$A=3863.345$

Interest = 3863.345 - 3500 = 363.345

Hence the total amount in an investment of $3500 that was compounded quarterly for 8 years at a rate of 5% is $3863.345 and the interest that was made on that account mentioned is $363.345

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4 years ago

Lenox ironed 1/4 of the shirts over the weekend. She plans to split the remainder of the work equally over the next 5 evenings.

MrMuchimi

3/20, or 0.15 of the shirts each evening

1 - 1/4 = 3/4

(3/4) / 5 = (3/4) / (5/1) = (3/4) x (1/5) = 3/20 = 0.15

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3 years ago

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15 minus the product of 5 times the difference of p minus 6

m_a_m_a [10]