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3 years ago

What multiplies to 5 and adds to 6

Mathematics

1 answer:

melisa1 [442]3 years ago

4 0

5 and 1 multiply to 5 and add to 6

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(adapted from Ross, 2.37) Your math professor gives you a set of 10 problems and tells you that the final exam will consist of a

soldier1979 [14.2K]

Answer:

(a) 1/2

(b) 9/10

Step-by-step explanation:

Probability is given by number of possible outcomes ÷ number of total outcomes

(a) Number of possible outcomes = 5 questions, number of total outcomes = 10 questions

Probability (I answer all 5 problems correctly) = 5/10 = 1/2

(b) Probability (I answer at least 4 of the problems correctly) means I either answer 4 of the problems or all 5 problems correctly = 4/10 + 5/10 = 9/10

3 0

3 years ago

Read 2 more answers

Factor the expression by finding the GCF. 16m2 − 12m

ziro4ka [17]

Answer:

4m(4m-3)

Step-by-step explanation:

16m^2 − 12m

16 m^2 = 2*2*2*2*m*m

12m = 2*2*3*m

The greatest factor for 16m^2 and 12m is 2*2*m or 4m

Factor out 4m

16 m^2 = 2*2*2*2*m*m = 4m(2*2m)=4m(4m)

12m = 2*2*3*m = 4m(3)

Factoring out 4m

16m^2 − 12m

4m(4m-3)

3 0

3 years ago

Read 2 more answers

Which of the following shows 204/72 as mixed number simplest form?

wariber [46]

The simplest form of 204/72
=17/6

3 0

3 years ago

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago

2(10.8 k+ 2.9) What's the answer

motikmotik

21.6k + 11.8

I believe is the answer good luck!

3 0

3 years ago