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rodikova [14]
3 years ago
12

A car drove 24 miles in 0.2 hours. How fast is the car going in miles per hour?

Mathematics
2 answers:
gladu [14]3 years ago
4 0

Answer:

  120 mph

Step-by-step explanation:

To find miles per hour, divide miles by hours. ("Per" essentially means "divided by".)

  (24 miles)/(0.2 hour) = 24/0.2 miles/hour = 120 miles/hour

kvasek [131]3 years ago
3 0
The answer is 120

Explication: 0.2 x 5 = 1 so since you multiplied 5 on one part you have to do it to the other and that gets you 120 miles per hour
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Answer:

I think it would be 1 out of 6 or B.

Step-by-step explanation:

I think so because there are 6 sides to a cube and if Mrs.Clever only rolls it once then it would be 1 out of 6.

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Which number sentence is not true?<br><br>A.<br>B.<br>C.<br>D.
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I can help if you put the number sentences in
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4 years ago
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Someone please be awesome and help me please :(
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Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

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I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

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(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

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x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

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