The class width for this Frequency Distribution Table is 5.
<h3>What is the class width?</h3>
The class width is the difference between the upper boundary and the lower boundary of the class.
The class width = upper boundary - lower boundary
5 - 0 = 5
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<h3>
Answer: $2400</h3>
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Explanation:
x = Mason's salary in dollars for that month
x/6 = one-sixth of his salary
x/6+800 = total amount spent (the x/6 dollars and $800 combined)
In total, he spent half his salary. This means he spent x/2 dollars for the month overall.
Set the two items equal to one another. Solve for x.
x/6 + 800 = x/2
6(x/6 + 800) = 6*(x/2) ... see note at the bottom of the page
x+4800 = 3x
4800 = 3x-x
4800 = 2x
2x = 4800
x = 4800/2
x = 2400
His monthly salary is $2400
1/6 of this is (1/6)*2400 = 2400/6 = 400 dollars. Add on the $800 he also spent to get a total of 400+800 = 1200 dollars spent, which is exactly one half of the $2400. The answer is confirmed.
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Note: I multiplied both sides by 6 to clear out the fractions. The value 6 is the LCD in this case.
The functions and their properties are
- The function f(x) has its vertical asymptote at x = 0
- The x-intercept of the function h(x) is (0.5,0)
<h3>How to match the functions and their properties?</h3>
The equations of the functions are given as:
f(x) = ln(x)
g(x) = -1/2f(x - 2)
h(x) = f(x - 1/2)
From the given graph, we can see that the function f(x) has its vertical asymptote at x = 0
h(x) = f(x - 1/2) implies that the function f(x) is shifted 1/2 units right to form h(x)
This means that the x-intercept of the function h(x) is 1/2 units to the right of the x-intercept of the function f(x)
Hence, the x-intercept of the function h(x) is (0.5,0)
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Incorect, you messed up on the second step. 7x4x is not 7x, it is 28x.
Answer:
It's not a right angle.
Step-by-step explanation:
Remark
There's a second restriction on the problem. The Perimeter is 22 cm.
AB = 8
BC = 5
AC = 9.4
When you add these up, you get 8 + 5 + 9.4 which is 22.4
You may think this is close enough. In this case it is not. Either the perimeter has to 22.4 or the hypotenuse has to be reduced. Let us say it is close, but not close enough.
When you use other methods, you find out that the right angle is actually 90.4 degrees
