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IRISSAK [1]
2 years ago
9

Find the distance between the point P(0, 0) and the line y = −x + 4 using the distance formula

Mathematics
1 answer:
Verdich [7]2 years ago
4 0

Answer:

The distance between the point P(0, 0) and the line y = −x + 4 is 2\sqrt{2} units.

Step-by-step explanation:

Distance between the point (x_0,y_0) and the line ax+by+c=0 is

d=\dfrac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}

The given equation is

y=-x+4

Taking all terms on the left side.

x+y-4=0

The distance between the point (0,0) and the line x+y-4=0 is

d=\dfrac{|0+0-4|}{\sqrt{1^2+1^2}}

d=\dfrac{|-4|}{\sqrt{2}}

d=\dfrac{4}{\sqrt{2}}

Rationalize denominator.

d=\dfrac{4}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}

d=\dfrac{4\sqrt{2}}{2}

d=2\sqrt{2}

Therefore, the distance between the point P(0, 0) and the line y = −x + 4 is 2\sqrt{2} units.

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