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blondinia [14]
3 years ago
11

Solve: 4-(9g-5)=-27 please help

Mathematics
2 answers:
scoray [572]3 years ago
6 0

Answer:

-18

if you need more info. just search up you question on Google and click the first link

8_murik_8 [283]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

9g-4-5=-27

9g-9=-27

Add 9 to both sides

9g=-18

g=-2

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3 years ago
Identify all the sets to which the number belongs. Choose from rational number, irrational number, whole number, an integer.
jek_recluse [69]

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Rational

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8 0
3 years ago
The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are
STALIN [3.7K]

Answer:

We conclude that the proportion of dropouts has changed from the historical value of 0.081.

Step-by-step explanation:

We are given that in 2009, the high school dropout rate was 8.1%. A polling company recently took a survey of 1000 people between the ages of 16 and 24 and found 6.5% of them are high school dropouts.

The polling company would like to determine whether the proportion of dropouts has changed from the historical value of 0.081.

<em>Let p = proportion of school dropouts rate</em>

SO, <u>Null Hypothesis,</u> H_0 : p = 0.081   {means that the proportion of dropouts has not changed from the historical value of 0.081}

<u>Alternate Hypothesis</u>, H_A : p \neq 0.081   {means that the proportion of dropouts has changed from the historical value of 0.081}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

             T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p  = sample proportion of high school dropout rate = 6.5%

            n = sample of people = 1000

So, <u><em>test statistics</em></u>  =   \frac{0.065-0.081}{{\sqrt{\frac{0.065(1-0.065)}{1000} } } } } 

                               =  -2.05

<u>Also, P-value is given by the following formula;</u>

         P-value = P(Z < -2.05) = 1 - P(Z \leq 2.05)

                                              = 1 - 0.97982 = <u>0.0202</u> or 2.02%

<em>Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the proportion of dropouts has changed from the historical value of 0.081.

7 0
3 years ago
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