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4 years ago

Describe a real life situation that can be represented as a system of inequalities.

2 answers:

6 0

Grapes are $3/pound. I have $30 to spend on grapes for the party. I know that if I buy less than 5 pounds I will not have enough? How much can I buy? x = the pounds

Novay_Z [31]4 years ago

3 0

John is two times older than Mike. But in the same time Mike is just 6 years younger then John. What is John's and Mike's age?

Here $x$ represents John's age and $y$ represents Mike's.
$\left \{ {{x=2y} \atop {x-6=y}} \right.$

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Write an expression with two terms. One term should have a coefficient with a variable and the other term should be a constant.

soldier1979 [14.2K]

Answer:

See Explanation

Step-by-step explanation:

Let us briefly explain the terms

Variable: This is the letter in the expression
Coefficient: This is the number beside the letter above
Constant: This is a number without any variable attached.

Let us take our expression with two terms to be: 3x+5

Coefficient =3

Variable =x

Constant =5

The word phrase of the expression is:

5 added to the product of 3 and a number.

3 0

4 years ago

1 yogurt cost 55p how many can be bought for £5

Alenkinab [10]

If one pound of yogurt cost 55 (cents?) then, Two yogurts cost $1.10
Three yogurts cost $1.65
Four yogurts cost $2.20
Five yogurts cost $2.75
Six yogurts cost $3.30

7 0

3 years ago

Find the distance between points P(9,8) and Q(7,6) to the nearest tenth.

sergey [27]

Answer:

2.8 units

Step-by-step explanation:

Think of this distance as the hypotenuse of a right triangle that has a vertical leg and a horizontal one as well.

Going from P to Q, the change in x is 2 and the change in y is also 2.

Thus, by the Pythagorean Theorem, this desired distance is:

d = √(2^2 + 2^2) = 2√2 units, or 2.8 units

6 0

3 years ago

A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.

Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

The probability that the birth is a male can be written as

$p(m) = 0.52$ (which corresponds to 52%)

While the probability that the birth is a female can be written as

$p(f) = 0.48$ (which corresponds to 48%)

Here we want to calculate the probability that over 2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

$p(mm)=p(m)\cdot p(m)$

And substituting, we find

$p(mm)=0.52\cdot 0.52 = 0.27$

So, 27%.

In this case, we want to find the probability that both children are female, so the probability

$p(ff)$

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

$p(ff)=p(f)\cdot p(f)$