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3 years ago

Please help how to solve

Mathematics

1 answer:

tatiyna3 years ago

7 0

Answer:

$= > in \: the \: bigger \: triangle \\ height = 14 \: ft \\ base = 22.5 \: ft \\ = > in \: smaller \: triangle \\ height = x \: ft \\ base = 9 \: ft \\ using \: ratios \\ \frac{bigger \: height}{smaller \: height} = \frac{bigger \: base}{smaller \: base} \\ \frac{14}{x} = \frac{22.5}{9} \\ \frac{14}{x} = 2.5 \\ x = \frac{14}{2.5} \\ x = 5.6 \: ft$

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3 years ago

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Type the correct answer in each box. Use numerals instead of words. Any non-integer answers in this problem should be entered as

ladessa [460]

Answer:

The interquartile range of the data set is 5

The mean absolute deviation of the data set is 3.6

Step-by-step explanation:

* Lets explain how to find the interquartile range and the mean absolute

deviation (MAD)

- The steps to find the interquartile range is:

1- Arrange the values from the smallest to the largest

∴ The values are 5 , 6 , 10 , 11 , 12 , 13 , 14 , 15 , 18 , 20

2- Find the median

- The median is the middle value after arrange them

* If there are two values in the middle take their average

∵ The values are 10 then the 5th and the 6th are the values

∵ The 5th is 12 and the 6th is 13

∴ The median = $\frac{12+13}{2}=12.5$

∴ The median is 12.5

3- Calculate the median of the lower quartile

- The lower quartile is the median of the first half data values

∵ There are 10 values

∴ The first half is the first five values

∴ The first half values are 5 , 6 , 10 , 11 , 12

∵ The middle value is 10

∴ The median of lower quartile = 10

- Similar find the median of the upper quartile

- The upper quartile is the median of the second half data values

∵ There are 10 numbers

∴ The second half is the last five values

∴ The second half values are 13 , 14 , 15 , 18 , 20

∵ The middle value is 15

∴ The median of upper quartile = 15

4- The interquartile range (IQR) is the difference between the upper

and the lower medians

∴ The interquartile range = 15 - 10 = 5

* The interquartile range of the data set is 5

* Lets talk about the mean absolute deviation

- Mean absolute deviation (MAD) of a data set is the average distance

between each data value and the mean

- To find the mean absolute deviation of the data, start by finding

the mean of the data set.

1- Find the sum of the data values, and divide the sum by the

number of data values.

∵ The data set is 5 , 6 , 10 , 11 , 12 , 13 , 14 , 15 , 18 , 20

∵ Its sum = 5 + 6 + 10 + 11 + 12 + 13 + 14 + 15 + 18 + 20 = 124

∵ The mean = the sum of the data values/the number of the data

∵ The set has 10 numbers

∴ The mean = 124/10 = 12.4

2- Find the absolute value of the difference between each data value

and the mean ⇒ |data value – mean|

# I5 - 12.4I = 7.4

# I6 - 12.4I = 6.4

# I10 - 12.4I = 2.4

# I11 - 12.4I = 1.4

# I12 - 12.4I = 0.4

# I13 - 12.4I = 0.6

# I14 - 12.4I = 1.6

# I15 - 12.4I = 2.6

# I18 - 12.4I = 5.6

# I20 - 12.4I = 7.6

3- Find the sum of the absolute values of the differences.

∵ Their sum = 7.4 + 6.4 + 2.4 + 1.4 + 0.4 + 0.6 + 1.6 + 2.6 + 5.6 + 7.6

∴ Their sum = 36

4- Divide the sum of the absolute values of the differences by the

number of data values to find MAD

∴ MAD = The sum of the absolute values/number of the values

∵ The sum = 36

∵ The data set has 10 values

∴ MAD = 36/10 = 3.6

* The mean absolute deviation of the data set is 3.6

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3 years ago

You are working part-time for an electronics company while going to high school. The following table shows the hourly

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Answer: 5

Step-by-step explanation:

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3 years ago

The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a

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Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

$\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{ }\times\text{ m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48 }\times\text{ 100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}$

Hence, there are 300 students.

$\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{ }\times\text{ 300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72 students} \end{gathered}$

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

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36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

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1 year ago

Adult red wolves vary in length from 137.16 cm to 168.64 cm. Estimate the difference in length between the longest and shortest

zhannawk [14.2K]

Answer:

As per the statement:

Adult red wolves vary in length from 137.16 cm to 168.64 cm.

To find the difference in length between the longest and shortest of these wolves.

Longest length of wolves = 168.64 cm

Shortest length of wolves= 137.16 cm

Then;

$\text{Difference of the length between the longest and shortest of these wolves}$ = $\text{Length of longest wolves} -\text{Length of shortest wolves}$

Substitute the given values we have;

$\text{Difference of the length between the longest and shortest of these wolves}$ = 168.64 - 137.16 = 31.48 cm

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3 years ago