All categories

3 years ago

BRANLIEST TO FIRST CORRECT ANSWER:

Mathematics

1 answer:

Nuetrik [128]3 years ago

8 0

It would be...C?? I'm not sure but I think it's right. Brainliest?

You might be interested in

Please help me this is due in 20 mins

vekshin1

Answer:

35cm

120cm^2

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

PPPPPPLLLLLLEEAAASSEE HELLLPPP WIL MARK BRAINLIEST the brackets for a shelf are in the shape of a triangle. Find the angles of t

ahrayia [7]

Answer:

Step-by-step explanation:

Sum of the angles of a triangle is ALWAYS 180°.

2x+3x+5x = 180°

10x = 180°

x = 18°

2x = 36°

3x = 54°

5x = 90°

The angles are 36°, 54°, and 90°

6 0

2 years ago

PLEASE HELP ME!!!!

tigry1 [53]

1/8x2 and 4x I had usa test prep

6 0

2 years ago

Read 2 more answers

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago

Susan traveled 57.9 miles each day for the past 7 days. How many miles did she travel in all?

Reika [66]

Answer:

Simply take the number of miles each day and multiply it by the number of days. 57.9 miles × 7 days = 405.3 miles

Answer: 405.3 miles

4 0

2 years ago