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Alik [6]
3 years ago
6

Please help!! Urgent matter!!

Mathematics
1 answer:
defon3 years ago
8 0

Answer:

your questions is not looking clearly

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Find the equation of the line passing through the points (2 11) and (-8 -19)
Svet_ta [14]

Answer:

Y=2x+7

Step-by-step explanation:

To find the gradient of the line u have to subtract the y intercepts and the x intercepts

11--9/2--8=20/10=2

Y-11/x-2=2

Y-11=2(x-2)

Y-11=2x-4

Y=2x-4+11

Y=2x+7

5 0
3 years ago
The square below has side 10x. Find the area of the square remaining after a circle of radius 2x is removed from the square; in
Anna [14]
Area of a square: side^2
Area of a circle: (pi)(radius^2)
A(square)=(10x)^2
A(circle)=(pi)(2x)^2
A(square)=100x^2
A(circle)=(pi)4x^2
Shaded Area=A(square)-A(circle)
Shaded Area=100x^2-(pi)4x^2
=4x^2(25-(pi))
4 0
4 years ago
Lissette's age is 3 years less than twice the age of her sister Francesca. Lissette is 13. Write an equation that can be used to
Katen [24]
 let  L be <span>Lissette's age

and F   </span><span>Francesca age 

2 F - 3 = 13 

2F= 16  

F = 16/2 =8

</span>
3 0
3 years ago
What is the simplified form of <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%206%7D%7B3%7D%20%20-%20%20%5Cfrac%7Bx%
solmaris [256]

Answer:

4/3

Step-by-step explanation:

x + 6 - (x + 2) / 3

= x - x + 6 - 2 / 3  

=  4/3

6 0
3 years ago
Read 2 more answers
1. The equation of the locus of a point which is always equidistant from the points (a + b, a - b) and (a - b, a + b) is a) x -
valina [46]

Answer:

c). y + x = 0

Step-by-step explanation:

The locus is a line perpendicular to the line connecting the 2 points and passing through the centre of the line.

The mid-point of the line connecting the given points is:

(a + b + a - b)/2 , (a - b + a + b) / 2

= (a, a)

It's slope = (a + b)- (a - b) / (a - b)- (a + b)

= 2b/ -2b

= -1

So the slope of the line we want is -1/(-1) = 1.

Using the point-slope form of a line:

y - y1 = m(x - x1)

y - a = 1(x - a)

y - a = x - a

x + y = 0

8 0
2 years ago
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