Answer:
193 mg
Step-by-step explanation:
Exponential decay formula:
- where Aₜ = mass at time t, A₀ = mass at time 0, r = decay constant (rate), t = time
Our known variables are:
- 1998 to the year 2004 is a total of t = 6 years.
- The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.
Let's solve for the decay constant of this sample.
Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.
Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.
The expected mass of the sample in the year 2011 would be 193 mg.
Answer:
Hi there, the answer is 1/3
Step-by-step explanation:
Answer:
14. 1/13
15. 14/15
16. 1/13
17. 15/30=1/2
18. 12/13
19. 12/15
If you are happy with my answers, please give brainliest <3
<em><u>10 subtracted from the quotient of a number and -3 is at least -1 is:</u></em>
![\left(\frac{x}{-3}\right)-10\ge \:-1\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-27\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-27]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7Bx%7D%7B-3%7D%5Cright%29-10%5Cge%20%5C%3A-1%5Cquad%20%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5C%3A-27%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A-27%5D%5Cend%7Bbmatrix%7D)
<em><u>Solution:</u></em>
<em><u>Given statement is:</u></em>
10 subtracted from the quotient of a number and -3 is at least -1
Quotient means reuslt of dividing two numbers
Let the number be "x"
quotient of a number and -3 = 
Therefore,
10 subtracted from is at least -1
at least means "less than or equal to"
<em><u>Which is translated into algebraic expression as:</u></em>
<em><u>Solve the above inequality</u></em>
When we multiply or divide by negative number. we have to flip the inequality sign
Thus the solution of inequality is found
