Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
Answer:
x = 8
Step-by-step explanation:
Since < A and < B are vertical angles, then it means that they have the same measure.
Given that m < A = (3x - 21)°, and m < B = (2x - 13)°:
We can set up the following equation to solve for the value of x:
m < A = m < B
(3x - 21)° = (2x - 13)°
3x - 21 = 2x - 13
Subtract 2x from both sides:
3x - 2x - 21 = 2x - 2x - 13
x - 21 = -13
Add 21 to both sides to isolate and solve for the value of x:
x - 21 + 21 = -13 + 21
x = 8
We must verify if we have the correct value for x by plugging in 8 into the equality statement:
(3x - 21)° = (2x - 13)°
[3(8) - 21]° = [2(8) - 13]°
(24 - 21)° = (16 - 13)°
3° = 3° (True statement. This means that we have the correct value for x).
Therefore, the value of x = 8.
Please mark my answers as the Brainliest, if you find this solution helpful :)
Answer:
380
Step-by-step explanation:
if you have 400 hundread you would subtract 5% from 400 amd you would get 380.
Okay, so if it leaks out a pint every hour, and a gallon is 8 pints, it will take 8 hours to leak out 1 gallon. Since there are 24 hours in a day, it would leak out 3 gallons every day. Now, assuming the month we are talking about is 31 days, then we multiply 31 with 3, giving us 93 gallons in a month.
Do you need help with the third too?
Answer:
your question is not complete or should I say not correct ☺️
