Plug the values into the second equation to see if they end up equaling 0.
-4: 2(-4)^2 - 6(-4) - 8 = 0
2(16) + 24 - 8 = 0
32 + 16 = 0
Not -4
-1: 2(-1)^2 - 6(-1) - 8 = 0
2 + 6 - 8 = 0
8 - 8 = 0
0 = 0
Yes -1
0: 2(0)^2 - 6(0) - 8 = 0
0 - 0 - 8 = 0
Not 0
1: 2(1)^2 - 6(1) - 8 = 0
2 - 6 - 8 = 0
-12 = 0
Not 1
4: 2(4)^2 - 6(4) - 8 = 0
2(16) - 24 - 8 = 0
32 - 32 = 0
0 = 0
Yes 4
————
Or use the quadratic equation ( - b +/- sqrt( b^2 - 4ac)) / 2a
————
a would be 2–
b would be -6–
& c is -8
3 consecutive numbers when the first one is x
x and x + 1 and x + 2 are ur numbers....and I am guessing ur wanting the sum, so ur expression is :
x + x + 1 + x + 2 or 3x + 3
6-2/2+5= 4/7=.57142857142 but usually you just keep it as a fraction so 4/7 is the answer
No.
.4444444 (repeats forever)
and 4/9 are the same number
X-(x+5) I'm pretty sure that's it.
