<h3>Given:</h3>
- P= $12500
- R= 10%
- T= 3 years
<h3>Note that:</h3>
- P= Principal amount
- R= Rate of interest
- T= Time period
<h3>To find:</h3>
- The simple interest
- The total amount paid
<h3>Solution:</h3>

First, we'll have to multiply, principal amount (12500), rate (10) and time period (3).


Now, we'll have to divide the amount (375000) by 100.

<em>I=$3750</em>
Now, we can find the total amount paid.

Let's substitute according to the formula.

<em>A=$16250</em>
<u>Therefore</u><u>,</u><u> </u><u>simple</u><u> </u><u>interest</u><u> </u><u>is</u><u> </u><u>$</u><u>3</u><u>7</u><u>5</u><u>0</u><u> </u><u>and</u><u> </u><u>$</u><u>1</u><u>6</u><u>2</u><u>5</u><u>0</u><u> </u><u>was</u><u> </u><u>paid</u><u> </u><u>in</u><u> </u><u>total</u><u>.</u>
Answer:
7/10 or 70%.
Step-by-step explanation:
There is a total of 20 marbles in the bag.
There are 10 + 4 = 14 marbles which are not blue.
The required probability = 14/20
= 7/10.
14 = 9 - p
Move 9 to the other side
Sign changes from +9 to -9
14-9= 9-9-p
14-9= -p
5=-p
Mutiply both sides by -1 to get + p
(5)(-1)= (-p)(-1)
p= -5
Answer: p= -5
Answer:
- Two sided t-test ( d )
- 0.245782 ( c )
- Since P-value is too large we cannot conclude that the students’ weight are different for these two schools. ( c )
- The test is inconclusive; thus we cannot claim that the average weights are different. ( b )
Step-by-step explanation:
1) Test performed is a Two sided test and this because we are trying to determine the mean difference between two groups irrespective of their direction
<u>2) Determine the P-value ( we will use a data-data analysis approach on excel data sheet while assuming Unequal variances )</u>
yes No
Mean 94.47059 89.76471
Variance 173.2647 95.19118
Observations 17 17
df 30
t Stat 1.184211
P(T<=t) one-tail 0.122814
t Critical one-tail 1.697261
P(T<=t) two-tail 0.245782
Hence The p-value = 0.245782
3) Since P-value is too large we cannot conclude that the students’ weight are different for these two schools.
4) The test is inconclusive; thus we cannot claim that the average weights are different.