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a. The probability that on a randomly selected day, the jail population
is greater than 750,000 is 20.1%
b. The probability that on a randomly selected day, the jail population is
between 600,000 and 700,000 is 43.2%
Step-by-step explanation:
The given is:
1. The average daily jail population in the United States is 706,242
2. The distribution is normal and the standard deviation is 52,145
3. We need to find the probability that on a randomly selected day,
the jail population is greater than 750,000
4. We need to find the probability that on a randomly selected day,
the jail population is between 600,000 and 700,000
a.
At first find z-score
∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard
deviation
∵ x = 750,000 , μ = 706,242 and σ = 52,145
∴ z = ≅ 0.84
Use the normal distribution table of z to find the area to the right of
the z-value
∵ The corresponding area to z-score of 0.84 is 0.79955
- But we are interested in x > 750,000, we need the area to the
right of z-score
∴ P(x > 750,000) = 1 - 0.79955 = 0.2005
∴ P(x > 750,000) = 0.2005 × 100% = 20.1%
The probability that on a randomly selected day, the jail population is
greater than 750,000 is 20.1%
b.
We will find z-score for 600,000 < x < 700,000
∵ z = ≅ -2.04
∵ z = ≅ -0.12
Use the normal distribution table of z to find the area between
the two z-values
∵ The corresponding area to z-score of -2.04 is 0.02068
∵ The corresponding area to z-score of -0.12 is 0.45224
- To find P(600,000 < x < 700,000) subtract the two values above
∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316
∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%
The probability that on a randomly selected day, the jail population is
between 600,000 and 700,000 is 43.2%
Learn more:
You can learn more about z-score in brainly.com/question/7207785
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It's easy once you spot the ones that can cross cancel!
Say we have the fractions 8/10 and 20/23. (it's easier to see on top of each other)
If you look diagonally , so 8 and 23 and 10 and 20, you can see that 10 and 20 have a common factor. So we divide it by the highest common factor to reduce those numbers, making it easier to multiply. 10 and 20 can become 1 and 2, dividing by 10. So now we are left with 8/1 and 2/23, and now we multiply normally going across so 16/23.
This works going both diagonals and simplifying both, but in that case it would be easier to try and simplify the fractions before cross multiplying them.
Basically: look for those diagonals and if they can be divided down by the highest common factor, go for it to make it easier to multiply normally afterwards.
Hope I helped!