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icang [17]
3 years ago
9

1+4=5 2+5=12 3+6=21 what is 8+11=

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0
8+11 is 19 Hope it helped
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Find the cosine of angle B.
Alexandra [31]

\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

-

9² = 12² + 15² - 2 (12) (15) cos (B)

81 = 144 + 225 - 360 cos(B)

81 = 369 - 360 cos (B)

360 cos (B) = 369 - 81

360 cos (B) = 288

cos (B) = 0.8

-

Answer: Cosine B = 0.8

-

\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

-

12² = 15² + 9² - 2 (15)(9) cos (A)

144 = 225 + 81 - 270 Cos A

144 = 306 - 270 Cos A

270 Cos A = 162

Cos A = 3/5 or 0.6

-

Answer: Cosine Angle A = 3/5

4 0
3 years ago
What makes this bond correct <br> 3/4+__=2<br> WHATS THE ANSWER
VladimirAG [237]

Answer:

The answer is 5/6.

Step-by-step explanation:

Lets start with a=1.

a+1=2, which is the denominator. (1/2)

Taking the same number as numerator, now, consider a=2.

a+1=3, denominator.(2/3)

Now, let a=3.

a+1==4, denominator for a=3. (3/4)

If continued a becomes equal to 4.

a+1=5, which is also the denominator. (4/5)

Now, since the denominator is 5, let a=5.

a+1=6, which will become the denominator. (5/6)

Thus the series follows a pattern of a/a+1.

4 0
2 years ago
Read 2 more answers
a figure has the coordinates (0,0) (0,15) and (8,0). If the figure is rotated about the y- axis, what is the volume of the shape
AfilCa [17]

Answer:

120

Step-by-step explanation:

15 x 16/2

You double 8 because your rotating around the y-axis

3 0
3 years ago
Help me ASAP PLEASE
tamaranim1 [39]

Answer:

Your(my) number is 40

Step-by-step explanation:

I. Given 80/something, + 13, * 5 = 75 when x is something

So [  \frac{80}{x} + 13 ]5 = 75

     [ \frac{400}{x} + 65] = 75

     \frac{400}{x} = 75 - 65

     \frac{400}{x}  = 10

     400 = 10x

        x = 40

II. Prove by replace 40 in x

    [(80/40) + 13]5 = 75

    [2 + 13] 5 = 75

    (15)5 = 75

        75 = 75 true

Ask me for anything.

5 0
2 years ago
Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,
alekssr [168]
Hey there :)

- tan²x + sec²x = 1    or    1 + tan²x = sec²x

sin²x + cos²x = 1 
Divide the whole by cos²x

\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}

\frac{sinx}{cosx} = tanx so \frac{sin^2x}{cos^2x} = tan^2x
and
\frac{1}{cosx} = secx so \frac{1}{cos^2x} = sec^2x

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0
3 years ago
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