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dusya [7]
3 years ago
15

Translate the following into an algebraic expression: a The number that is 40% more than five more than a number a.

Mathematics
2 answers:
dybincka [34]3 years ago
8 0

Answer:

x = a + 8

Step-by-step explanation:

x = The number that is 40% more than five more than a number a.

x = 40% more than 5 (plus a)

5 * 0.6 = 3

5+3 = 8

x = a + 8

MariettaO [177]3 years ago
7 0
The answer is x=8+9.
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Annalise withdraws $22.50 each day from her account for a week. How can you represent the change in her account after 2 weeks?
nadya68 [22]

Answer: She would have $315

Because there are 7 days in a week so you multiply 22.50 by 7 and you get 157.5, Then because she does it for two weeks you multiply 157.5 by 2 and you get 315

Hope this helps

8 0
4 years ago
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another one, pls help me im desperate my grades r pretty good but im so confused on this and its a big percentage of my grade PL
pav-90 [236]

Answer:

70 to 220 i think im confused to

Step-by-step explanation:

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3 years ago
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What is the volume of a sphere that has a diameter of 36 yd?
Katen [24]
Volume=(4/3)pi(r^3)

radius=1/2diameter
d=36
radius=1/2 36
radius=18


subsitute
volume=4/3 pi 18^3
volume=4/3 pi 5832
volume=23328/3 pi
volume=7776pi

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volume=7776 times 3.14
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8 0
4 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4   b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

7 0
3 years ago
(y+6)^2-(y-2)^2 <br><br> I got 16y+26 but it is wrong?
Gemiola [76]

Answer:

16y + 32

Step-by-step explanation:

Expand each term.

(y+6)² - (y-2)²

= (y+6)(y+6) - (y-2)(y-2)

= y² + 12y + 36 - (y² - 4y + 4)

Subtract the second group by changing each term's signs

= y² + 12y + 36 - y² + 4y - 4

Collect like terms

= 16y + 32

5 0
3 years ago
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