Answer:
p=-6
q=3
Step-by-step explanation:
5p-3q=-39
-2p-3q=3
Multiply the second equation by -1
2p +3q = -3
Add the first equation and the modified second equation
5p-3q=-39
2p +3q = -3
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7p = -42
Divide by 7
7p/7 = -42/7
p = -6
Now we can find q
2p +3q = -3
2(-6) +3q = -3
-12 +3q = -3
Add 12 to each side
-12+12 +3q = -3+12
3q = 9
Divide by 3
3q/3 = 9/3
q=3
14/99
Select 1 marble; the chance that it is white is 4/12. Select a 2nd marble; the chance that it is white is 3/11. Select a 3rd; the chance it is white is 2/10. Select a 4th; the chance it is red is 8/9. Select a 5th; the chance it is red is 7/8. The chance of getting this specific set of 5 marbles in this order is (4/12)×(3/11)×(2/10)×(8/9)×(7/8)=(2×7)/(11×10×9).
This specific set could occur in the permutation of 5 things taken 5 at a time where 3 are identical (white), and the other 2 are also identical (red). The formula for this is 5!/(3!2!)=10.
Combining the chance of getting white, white, white, red, red with the number of ways 3 white and 2 red could have been distributed in the draw of 5 marbles gives the answer:
{(2×7)/(11×10×9)}×10=14/99
A similar process will show that the chance of getting 5 red marbles is 7/99; 4 white and 1 red is 1/99; 2 white and 3 red is 42/99; and 1 white and 4 red is 35/99.
Answer: m = 2b/v
Step-by-step explanation:
Answer:
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