The equation of the line is y = -2x + 16 which passes through the point (4, 8) and has a slope of -2.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that:
The line that passes through the point (4, 8) and has a slope of -2.
On comparing the standard equation:
y = mx + c
Here m is the slope of the line and c is the y-intercept.
m = -2
y = -2x + c
Plug x = 4 and y = 8
8 = -2(4) + c
c = 16
y = -2x + 16
Thus, the equation of the line is y = -2x + 16 which passes through the point (4, 8) and has a slope of -2.
Learn more about the linear equation here:
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Answer:
(a) 7 essays and 29 multiple questions
(b) Your friend is incorrect
Step-by-step explanation:
Represent multiple choice with M and essay with E.
So:
--- Number of questions
--- Points
Solving (a): Number of question of each type.
Make E the subject of formula in
Substitute 36 - M for E in
Collect Like Terms
Divide both sides by -4
Substitute 29 for M in
Solving (b): Can the multiple questions worth 4 points each?
It is not possible.
See explanation.
If multiple question worth 4 points each, then
would be:
Where x represents the number of points for essay questions.
Substitute 7 for E and 29 for M.
Subtract 116 from both sides
Make x the subject
Since the essay question can not have worth negative points.
Then, it is impossible to have the multiple questions worth 4 points
<em>Your friend is incorrect.</em>
Answer:
50 km/hr
Step-by-step explanation:
OK, this is how I solved this problem.
Let r = original rate of speed
t = time after the stop to finish the trip
Time for trip without stopping is 225/r
(1) 1.5 + .5 + t = 225/r This is a time equation
(2) 1.5r + t(r + 10) = 225 This is a distance equation
(1) 2 + t = 225/r (2) 1.5r + tr + 10t = 225
2r + tr = 225
tr = 225 - 2r 1.5r + 225 - 2r + 10(225/r - 2) = 225
t = 225/r - 2
-.5r + 225 + 2250/r - 20 = 225
-5r + 2250 + 22500/r - 200 = 2250
-5r^2 + 2250r + 22500 - 200r = 2250r
5r^2 + 200r - 22500 = 0
5(r^ + 40r - 4500) = 0
5(r - 50)(r + 90) = 0
r = 50 or r = -90
The rate cannot be negative, so the original speed 50 km/hr
This not an easy problem and I hope you were able to follow my work
A=p (1+r/k)^kt
A=500×(1+0.02÷3)^(3×4)
A=541.50
Answer:
Step-by-step explanation:
<u>Given equation:</u>
<u>Divide both sides by 20:</u>
<u>Simplify:</u>
