Maurice wants to create a set of elliptical flower beds. To do this, he first plots the location of the two fruit trees on his graph.
Maurice has to use the equation a^2-b^2=c^2. We know that c=3, and because we need 1 more number to solve for b, I made a=6. 6^2-b^2=3^2. 36-b^2=9. b^2=27. b=5.196
<span>Next, to create the equation, we substitute what we know into the equation x^2/a^2 + y^2/b^2=1 and get x^2/36 + y^2/27=1. Johanna wants to create some hyperbolic flower beds.
We already know that c=3 so this time I decided a=1. 3^2=1^2+b^2. 9=1+b^2. 8=b^2. b=2.828
Next, to create the equation, we substitute what we know to the equation x^2/a^2 - y^2/b^2 = 1. x^2/1^2 - y^2/2.828^2 = 1. </span>
Answer:
HL
Step-by-step explanation:
The hypotenuse and the "leg" are congruent...along with the 90 degree angle.
"The HL Postulate states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent." - Calcworkshop
6 1/3 + k + 3 5/6 + 5 1/2 = 26 1/6
Add your fractions
6 1/3 + 3 5/6 + 5 1/2 = 15 2/3
now You need to isolate k on one side of the equation by using the subtraction method of equality.
k + 15 2/3 = 26 1/6
k = 10 1/2
Hope this helps
I had to edit
The answer is D. Call number of tickets is ‘x’ and amount $ collected is ‘y’. If x=5, y=3x5=15.
Step-by-step explanation:
a.) the given term can be written as
=
=
=
hence the given term is
where b = 3
b.)
=
=
=
=
hence the given term is 12
