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4 years ago

Find the surface area

Mathematics

2 answers:

stellarik [79]4 years ago

7 0

I hope this helps you

2.5.8+2.3.8+2.3.5

80+48+30

158

kenny6666 [7]4 years ago

3 0

Surface Area = 2×(5×3 + 5×8 + 3×8) = 158 inch2

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A scientist changes the temperature of a solution at a rate of

Anton [14]

Answer: A 9 min

Step-by-step explanation: 54/6=9

-6-6-6-6-6-6-6-6-6=-54

3 0

3 years ago

How much is the difference in yearly median income for a female versus male at a masters degree level?

ale4655 [162]

Answer: the difference in yearly median income for a female vs male at a masters degree level is

$15,642.90/year

Step-by-step explanation:

there are roughly 52.143 week in a year.

the median weekly income for a female with a masters degree is : $901.00

the median weekly income for a male with a masters degree is :

$1,201

so if you multiply $901 x 52.143 you get :

$46,980.84, which is what a female makes in a year with a md

and if you multiply $1,201 x 52.143 you get :

$62,623.74, which is what a male makes in a year with a md

subtract $62,623.74 - $46,980.84 you get :

$15,642.90 / year

7 0

4 years ago

How many times does 6 go into 22

sergeinik [125]

Hey!

We can use long division to solve this,
Let's write it.
$6\overline{|\smallspace22}\space\space\space\space$
Then, divide $22$ by $6$ to get $3$ .
$\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}$
Multiply the quotient by the divisor...
$\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace8}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}$
Subtract $18$ from $22$ .
$\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace8}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\space\space\emptyspace4\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}$
As you can see, our answer using long division would be 3 with a remainder of 4.

Thanks!
-TetraFish

6 0

4 years ago

Read 2 more answers

HELP IF RIGHT WILL MARK BRIANLIEST!! NO LINKS!!!!!!!

Brrunno [24]

Answer:

14 is the simplified answer, but the whole answer is 17 + -18/6

Step-by-step explanation:

Divide

−

18 by 6. h (−18) = 17 − 3 Subtract 3 from 17. h (−18)= 14

The final answer is 14.

8 0

3 years ago

Read 2 more answers

Over 500 million tweets are sent per day (digital Marketing ramblings website, December 15, 2014). Assume that the number of twe

Aleksandr [31]

Answer:

(a) The probability that Bob receives no tweets during his lunch hour is 0.0002.

(b) The probability that Bob receives at least 4 tweets during his lunch hour is 0.9190.

(d) The probability that Bob receives no tweets during the first 30 minutes of his lunch hour is 0.0302.

Step-by-step explanation:

Let X = number of tweets.

The random variable X follows a Poisson distribution with parameter λ = 7.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-7}(7)^{x}}{x!};\ x=0, 1, 2, 3...$

(a)

Compute the probability that Bob receives no tweets during his lunch hour as follows:

$P(X=0)=\frac{e^{-7}(7)^{0}}{0!}\\=\frac{0.000192\times1}{1} \\=0.000192\\\approx0.0002$

Thus, the probability that Bob receives no tweets during his lunch hour is 0.0002.

(b)

Compute the probability that Bob receives at least 4 tweets during his lunch hour as follows:

P (X ≥ 4) = 1 - P (X < 4)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-7}(7)^{0}}{0!}-\frac{e^{-7}(7)^{1}}{1!}-\frac{e^{-7}(7)^{2}}{2!} - \frac{e^{-7}(7)^{3}}{3!}\\=1-0.0002-0.0064-0.0223-0.0521\\=0.9190$

Thus, the probability that Bob receives at least 4 tweets during his lunch hour is 0.9190.

(c)

The average number of tweets in 60 minutes is 7.

Then the average number of tweets in 1 minute is, $\frac{7}{60}$ .

Hence, the average number of tweets during 30 minutes is, $\frac{7}{60}\times30=3.5$

Thus, the expected number of tweets Bob receives during the first 30 minutes of his lunch hour is 3.5.

(d)

Compute the probability that Bob receives no tweets during the first 30 minutes of his lunch hour as follows:

$P(No\ tweets) = \frac{e^{-3.5}(3.5)^{0}}{0!}=\frac{0.0302\times1}{1} =0.0302$

Thus, the probability that Bob receives no tweets during the first 30 minutes of his lunch hour is 0.0302.

3 0

4 years ago