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11Alexandr11 [23.1K]
4 years ago
12

Eva and Jamir like to bake cookies. Eva baked 242424 chocolate chip cookies, and Jamir baked ppp peanut butter cookies. Together

they baked a total of 565656 cookies.
Write an equation to describe this situation.
Mathematics
1 answer:
Aleksandr-060686 [28]4 years ago
4 0

Answer: The equation is 24 + x = 56

Step-by-step explanation: x would be 32, but the set up would be 24 + x = 56, since both of their cookies equal 56.

(Im also assuming you meant 24 and not 242424, same with 56.

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Find the fifth term of a geometric sequence for which a3= 20 and r= 2.
Dahasolnce [82]

Answer:

The fith number is 80.

Step-by-step explanation:

A geometric sequence is a group of numbers that are related to it's neighbours by a product of a constant ratio. In order to calculate a certain number in such sequences we can use the formula:

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Where "n" is the position of the number we wish to know and q is the ratio. To use the formula we need to know the first number and we were given the third, so we first need to find that. We have:

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4 0
3 years ago
A student is factoring 18x + 6x. Find the students mistake and correct it. 18x + 6x = 6x(3)=18x
Fiesta28 [93]

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6 0
2 years ago
A contaminant is leaking into a lake at a rate of R(t) = 1700e^0.06t gal/h. Enzymes that neutralize the contaminant have been ad
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Answer:

16,460 gallons

Step-by-step explanation:

This is a differential equation problem, we have a constant flow of contaminant into the lake, but also we know that only a fraction of that quantity of contaminant remains because of the enzymes. For that reason, the differential equation of contaminant's flow into the lake would be:

\frac{dQ}{dt} =1700exp(0.06t)*exp(-0.32t)\\\frac{dQ}{dt} =1700exp(-0.26t)\\

Then, we have to integrate in order to find the equation for Q(t), as the quantity of contaminant in the lake, in function of time.

\int\limits^0_t {dQ}=\int\limits^0_t {1700exp(-0.26t)dt}\\Q(t)=\frac{1700}{-0.26} exp(-0.26t)+C \\

Now, we use the given conditions to replace them in the equation, in order to solve for C

t_{0} =0\\Q_{0}=10,000\\Q_{0}=-6538exp(-0.26*0)+C\\C=10,000+6538=16538

Then, we reorganize the equation and we replace t for 17 hours, in order to determine the quantity of contaminant at that time:

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3 0
3 years ago
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