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2 years ago

What is the slope-intercept equation of the line below?

Mathematics

1 answer:

Gennadij [26K]2 years ago

6 0

Answer:

Step-by-step explanation:

(-1, 1) (1, -3)

(-3 - 1)/(1 + 1)= -4/2 = -2

y - 1 = -2(x + 1)

y - 1 = -2x - 2

y = -2x - 1

answer is A

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If I was trying to find the mode of the numbers 4,1,4,3,2 and 1, Which one is the mode if there is 2 of 4 and 2 of 1??

Burka [1]

The answer would be both

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3 years ago

Read 2 more answers

An investment project involves an immediate outlay of $8 million. The net cash flows received at the end of years 1, 2, and 3 wi

My name is Ann [436]

Answer:

(c) 0.46 million

Step-by-step explanation:

As provided immediate cash outlay = $8 million.

This will represent cash outflow at period 0, as it is made immediately, no time period has lapsed.

Cash inflows as provided and the respective present value factor are:

Year Cash Inflow Factor Discounted Value

1 $3 million 0.9091 $2,727,300

2 $4 million 0.8264 $3,305,600

3 $2 million 0.7513 $1,502,600

Total present value of cash inflow = $7,535,500

Therefore, net present value = $7,535,500 - $8,000,000 = - $464,500

That is - 0.46 million

Correct option is

(c) 0.46 million

4 0

3 years ago

What are th zeros of f(x)=x(x-8)

Andrews [41]

Hi there!

Let's solve this problem step by step!
The zeros of a function are the input values that produce an outcome of 0. To find this input values we must set up and solve an equation.

$f(x) = x(x - 8)$
Set up the equation

$f(x) = 0$ thus $x(x - 8) = 0$

Now use the rule AB = 0 gives A = 0 or B = 0. This rule basically means that if we have a product that equals 0, at least one of the factors must be 0.

Hence, we get the following:
$x = 0 \: \: or \: \: x - 8 = 0$

Finally add 8 to both sides in the right equation.
$x = 0 \: \: or \: \: x = 8$

The zeros of the function are 0 and 8.
~ Hope this helps you!

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3 years ago

Find dy/dx by differentiating implicitly <br> x^2y+3xy^3-x=3

AleksandrR [38]

$\dfrac{\mathrm d}{\mathrm dx}\left[x^2y+3xy^3-x\right]=\dfrac{\mathrm d}{\mathrm dx}[3]$
$2xy+x^2\dfrac{\mathrm dy}{\mathrm dx}+3y^3+9xy^2\dfrac{\mathrm dy}{\mathrm dx}-1=0$
$(x^2+9xy^2)\dfrac{\mathrm dy}{\mathrm dx}=1-2xy-3y^3$
$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{1-2xy-3y^3}{x^2+9xy^2}$

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3 years ago

3/2+×= -7/2 i. dont know how to solve for x i dont know the answer

GuDViN [60]

So you have to get x by itself first, but you have to do the same thing on both sides in order for it to stay equal.
3/2*2/3+x=-7/2*2/3
6/6+x=-14/6
x=-14/6
Simplify.
x=-7/3 or -2 1/3

Hope this helps! If you have any questions, just ask!

3 0

4 years ago