Answer:
24f + 12g - 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
4(6f + 3g - 1)
<u>Step 2: Expand</u>
- [Distributive Property] Distribute 4: 4(6f) + 4(3g) + 4(-1)
- Multiply: 24f + 12g - 4
Answer:
x < 6.5
y < -1.5
Step-by-step explanation:
y > x - 8
Therefore x < y + 8
y < 5 - x
Therefore x < 5 - y
2x < 13
x < 6.5
6.5 < 5 - y
y < -1.5
-4(z-12) = 42
First, we will get rid of the brackets by multiplying each term within the brackets by -4 as follows:
-4(z) - -4(12) = 42
-4z + 48 = 42
Then, we will isolate the term with the variable. To do so,we will simply subtract 48 from both sides as follows:
-4z+48-48 = 42-48
-4z = -6
Finally,we will get rid of the coefficient next to the variable by dividing both sides by -4.
The final result will thus be:
z = 3/2
Answer:
LCM (7, 18 and 21) = 126
Step-by-step explanation:
Step 1: Address input parameters & values
Intergers: 7 18 21
LCM (7, 18, 21) = ?
Step 2: Arrange the group of numbers in the horizontal form with space or comma separated format
7, 18 and 21
Step 3: Choose the divisor which divides each or most of the integers of in the group (7, 18 and 21), divide each integers separately and write down the quotient in the next line right under the respective integers. Bring down the integer to the next line if the integer is not divisible by the divisor. Repeat the same process until all the integers are brought to 1.
Step 4: Multiply the divisors to find the LCM 7, 18 and 21
7 × 3 × 6 = 21
LCM(7, 18, 21) = 126
The least common multiple for three numbers 7, 18, and 21 is 126
Answer:
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