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3 years ago

What is 26364 of 58474337373745493

Mathematics

1 answer:

Delvig [45]3 years ago

6 0

Of means you're multipling. So just multiply them together :)

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A circle has an area of 200.96 units2 and a circumference of 50.24 units. If the radius is 8 units, what can be said about the r

AleksandrR [38]

Answer:

C. The ratio of the area to the circumference is equal to half the radius.

Step-by-step explanation:

The area of a circle can be written as;

Area A = πr^2

The circumference of a circle is;

Circumference C = 2πr

Using the formula, w can derive the relationship between the two variables.

A = kC

k = A/C

Substituting the two formulas;

k = (πr^2)/(2πr) = r/2

So,

A = (r/2)C

A/C = r/2

The ratio of the area to the circumference is equal to half the radius.

Given;

Area = 200.96

Circumference = 50.24

Radius = 8

To confirm;

k = r/2 = 8/2 = 4

Also,

A/C = 200.96/50.24

A/C = 4

6 0

3 years ago

(-15)(-4) help meeee

Hunter-Best [27]

The answer is 60 (wow this was a fast answer wish people answered my questions this fast)

3 0

3 years ago

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I need help with this math question 3f+9<21

liubo4ka [24]

I am assuming you want to find the simplest form of the inequality.

1. $3f + 9 \ \textless \ 21$
2. $3f < 12$
3. $f < 4$

1. Start
2. Subtract 9 from each side
3. Divide both sides by 3

8 0

2 years ago

Help omg if so thank you.

Goshia [24]

Answer:

Step-by-step explanation:

49*5/7

=35

7 0

3 years ago

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A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$