If graph of the function y=f(x) was shifted to the right 1 unit, then you got new function y=f(x-1).
Reversly, if you have the function
that is obtained by shifting to the right 1 unit, then the initial function was
.
Answer: Correct choice is D.
Answer:
The mean and standard deviation of the number preferring the incumbent is mean = 330, standard deviation = 10.59.
Step-by-step explanation:
We are given that From previous polls, it is believed that 66% of likely voters prefer the incumbent.
A new poll of 500 likely voters will be conducted. In the new poll the proportion favoring the incumbent has not changed.
Let p = probability of voters preferring the incumbent = 66%
n = number of voters polled = 500
<u>So, the mean of the number preferring the incumbent is given by;</u>
Mean = 
= 
= 330 voters
<u>And, standard deviation of the number preferring the incumbent is given by;</u>
Variance = 
= 
= 112.2
So, Standard deviation = 
= 
= 10.59
20*282= 5640
10680-5640=5040
50-20=30
5040 dividend by 30= 168
Answer: 168
Answer:
16 and 18
Step-by-step explanation:
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
