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2 years ago

11

A rectangular auditorium seats 3332 people. The number of seats in each row exceeds the number of rows by 19. Find the number of

seats in each row.

1 answer:

Amiraneli [1.4K]2 years ago

3 0

Answer:175.368421

Step-by-step explanation:

I'm not sure if this is right but I think you have to divide the 3,332 people by the 19 rows.

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The surface area of 3ft, 7ft, 2ft

Xelga [282]

Answer: 82 ft squared

Step-by-step explanation: The surface area is 2( wl + hl + hw)

so the width is 2 the length is 7 and the height is 3

so it's 2( 14 + 21 + 6) = 2(41) = 82

6 0

3 years ago

Perform the following operation, and report the answer to the correct number of significant figures. 3.47 x 6.7

kobusy [5.1K]

Answer:

23

Step-by-step explanation:

3.47 = 3 sig. figs.

6.7 = 2 sig. figs.

Since these two numbers are being multiplied, you would round to the smallest number of sig. figs. of the two. In this case, it would be 2 significant figures.

3.47 * 6.7 = 23.249 (dont forget to round to 2 sig. figs. ) --> 23

6 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

(Easy) For the following quadratic function, find the axis of symmetry, the vertex and the y-intercept. y = x^2 + 12x + 32

hammer [34]

Answer:

$y ( \times + 6) 2 - 4$

7 0

3 years ago

Read 2 more answers

I need help on this test. Will give Brainliest to whoever answers first! Pt. 7

Gre4nikov [31]

I think the first question is A)

6 0

3 years ago