I don't understand at all. Please give me all the details about this thing

Mathematics

2 answers:

DerKrebs [107]3 years ago

7 0

I know that B is orthographic.
D is isometric.
A is a net.
C is none.

gizmo_the_mogwai [7]3 years ago

3 0

To do a net drawing<span> you have to cut the object so you can display all its sides in 2D.
</span>An orthographic drawing is 3D object drawn in 2D from 3 points of view: front, left/right and top.
An isometric drawing is 3D object displayed in 2D by rotating it 45 degrees to left/right and 45 degrees upward/downward.

So the correct answers are:
A - net, B - orthographic, C & D - isometric.

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Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .