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ZanzabumX [31]
3 years ago
11

100 POINTS AND BRAINLIEST PLEASE HELP ASAP!!!

Mathematics
2 answers:
svetlana [45]3 years ago
7 0
The answer is false there can be many different ways to do it
horrorfan [7]3 years ago
6 0

Answer:

The answer is false.

Dawg, brainliest please.

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Reid just got a pet feeder for his cats and filled it with 8 cups of food. The feeder will
Solnce55 [7]

Answer:

I think 7 days for 7 cups.

Step-by-step explanation:

6 0
3 years ago
Mr. Marzano taught 150 students at the high school. The following year he started teach elementary students and had 22 students.
GenaCL600 [577]

Answer:

85%(estimated)

Step-by-step explanation:

150-22=128

changed ÷ original x 100%

128 ÷ 150 x 100%

≈ 85%

3 0
3 years ago
Which name gives the most information about the shape below?
Scrat [10]

Answer:

trapezoid

Step-by-step explanation:

There is only one group of shapes that could be a trapezoid

A square, a rectangle, a rhombus, a trapezoid, a kite, and other 4-sided shapes fall under the category of quadrilateral

A rhombus, a parallelogram, and a square are all rhombuses

5 0
3 years ago
A delivery truck drives three routes in one day. The first route is 1223 miles long, the second route is 1034 miles long, and th
avanturin [10]

Answer:

Total = 38\frac{11}{12}\ miles

Step-by-step explanation:

Given

First\ Route = 12\frac{2}{3}\ miles

Second\ Route = 10\frac{3}{4}\ miles

Third\ Route = 15\frac{1}{2}\ miles

Required

Determine the total miles

Total = First\ Route + Second\ Route + Third\ Route

Total = 12\frac{2}{3} + 10\frac{3}{4} + 15\frac{1}{2}

Convert to improper fractions

Total = \frac{38}{3} + \frac{43}{4} + \frac{31}{2}

Take LCM

Total = \frac{152 + 129 + 186}{12}

Total = \frac{467}{12}

Total = 38\frac{11}{12}\ miles

5 0
3 years ago
A student in wildlife management studied trout habitat in the upper Shavers Fork watershed in West Virginia. The springtime wate
nataly862011 [7]

Answer:

C. H 0 : μ = 7 vs. Ha : μ ≠ 7

Since the calculated value of t = -9.462 falls in the critical region  t ≤-2.048

We conclude that the  springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

Step-by-step explanation:

The null hypothesis the usually the test to be performed. Here we want to check whether the water is neutral or not. Neutral water must have a pH of 7 . This can be stated as the null hypothesis. And the claim is treated as the alternate hypothesis that water in not neutral or not having pH= 7

In symbols it will be written as

H0: : μ = 7 vs. Ha : μ ≠ 7

So choice C is the best option for this hypothesis testing.

Let the significance level be 0.05

The degrees of freedom = n-1= 29-1 = 28

The critical value is  t ≥ 2.048 and t ≤ - 2.048 for 0.05 two tailed test with 28 df.

The test statistic to use is t- test

t= x- u/ s/√n

The total sum is 170.9 and mean = x= 5.893

The u = 7

And the sample standard deviation is =s= 0.63

Putting the values

t= 5.893-7/0.63/√29

t= - 1.107/0.11699

t= -9.4623

Since the calculated value of t = -9.462 falls in the critical region  t ≤-2.048

We conclude that the  springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

4 0
3 years ago
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