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Effectus [21]
2 years ago
11

Help please!! Can you show work so I can understand it!

Mathematics
1 answer:
Whitepunk [10]2 years ago
6 0
Side u = 8 units

Explanation:

(The triangle is a right triangle so we can use trigonometry to find u.)

(If you look from angle 45 degrees’ view: u is opposite, v is adjacent and 8 sqrt(2) is the hypotenuse because it is opposite to the right angle.)

sin = Opposite/Hypotenuse

sin(45) = u/[8 sqrt(2)]
sin(45) x 8 sqrt(2) = u
8 = u
u = 8 units
You might be interested in
How many rows are needed to seat all students. When there are 846 students and each row holds 18 people
lubasha [3.4K]

Answer:

47 rows

Step-by-step explanation:

To find the amount of needed rows, we will use the math operation division. We will take the total and divide it by the amount in each row.

846/18=47

To seat 18 people in each row, you will need 47 rows.

6 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST<br> Answer all parts of the question please!
Schach [20]
A: l x w = a formula for area
l = w + 48 length
w(w+48) = 3024 substitute l with w+48
w^2 + 48w -3024=0 —solution to part A

B: w^2 + 48w - 3024 = 0 factor
(w-36)(w+84) = 0
Solutions for width = 36,-84
A width can’t be negative, so the width is 36 inches


7 0
2 years ago
The function f(x)=5x+4f(x)=5x+4 models the height of a tree, where x represents the years since the tree was planted for year 3
Romashka [77]
"<span>all real numbers between 3 and 10 inclusive" could not be the answer, because these are x-values (values of the independent variable).

"</span><span>all real numbers between 19 and 54 inclusive" is the range.  Why?  Because in year 3, f(3) = height of tree = 5(3) + 4 = 19 feet.  

In year 10, f(10) = 5(10) + 4 = 54 feet. </span>
6 0
3 years ago
Find the area of the figure.
Contact [7]

area of rectangle= 8*13=104m^2

base of the Triangle= 13 -(4+4)=5

area of Triangle = 5*6/2=15m^2

area of shaded shape =104-15= 89m^2

7 0
2 years ago
Which points are solutions to the system of inequalities shown below? Check all that apply.
Alexandra [31]
I: y<2*x
II: y<8
III: x>2

a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution

b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution

c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution

d: (1,-4):
I: -4<2*1
-4<2 ?yes
II: -4<8 ?yes
III: 1>2 ?no
This is not a solution

e: (4,-2):
I: -2<2*4
-2<8 ?yes
II: -2<8 ?yes
III: 4>2 ?yes
This is a solution

f: (5,9):
I: 9<2*5
9<10 ?yes
II: 9<8 ?no
This is not a solution

so a,b,c,e are solutions and d,f not
6 0
3 years ago
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