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scoundrel [369]
4 years ago
8

Find the zeros of y = 3x^2+3x

Mathematics
1 answer:
iren [92.7K]4 years ago
4 0
The zeros of <span>y = 3x^2+3x  means to solve for the values of x when y = 0

</span> <span>y = 3x²+ 3x =0
</span>
<span>y = 3x²+3x  = 0
</span>
<span>3x²+3x  = 0                  Factorize

3x(x + 1) = 0

3x = 0,  or (x + 1) = 0

From 3x = 0,  x = 0/3 =0

From (x + 1) = 0,  x = 0 -1 = -1.

Therefore the zeros are 0 and -1.
</span>
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If the area of the right triangle is 72 what is the value of x
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36 i guess ha please that not right

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3 years ago
Mario is constructing a frame for 10 in. by 8 in. photo. He wants the frame to be the same with all the way around in the same a
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Answer: 12 in. by 10 in.

Step-by-step explanation:

Given: The dimensions of photo is 10 in. by 8 in.

Therefore, Area of photo= 10\times8=80\ in.^2

Area of frame with photo=120 square inches

Let x be the width of the frame, then we have

Length of frame with photo= 10+2x inches

Width of frame with photo =8+2x inches

Now, (10+2x)(8+2x)=120

80+16x+20x+4x^2=120\\\Rightarrow\ 4x^2+36x-40=0\\\Rightarrowx^2+9x-10=0\\\(x-1)(x+10)=0\\\Rightarrow\ x=1,...........[text{Since length can not be negative so it cannot be -10}]

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5 0
4 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
Furkat [3]

Answer:

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Step-by-step explanation:

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So, first we will find the derivative of the function. The derivative is:

f'(x)=3x^2 +6x-72

Now, we are going to make the derivative equal zero and find the answers of the equation.

3x^2 +6x-72=0\\3(x^2 +2x-24)=0\\3(x+6)(x-4)=0\\

So we have that the critical points are the answers to this equation:

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and

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Step-by-step explanation:

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Answer:

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