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pochemuha
3 years ago
15

Which explanation justifies how the area of a sector of a circle is derived?

Mathematics
1 answer:
nignag [31]3 years ago
3 0
The sector of a circle is drawn by drawing two radii intercepting an arc. The area of the sector is calculated by calculating first the area of the whole circle. Then, this value is multiplied by the ratio the measure of the intercepted arc to one whole revolution. The answer to this item is the THIRD OPTION. 
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The circumference of a circular painting is 53.38 feet. What is the radius of the painting? Use 3.14 for pi and do not round you
bazaltina [42]
The circumference or perimeter of the circle has the formula 2*pi*r, where r is the radius of the circle. This could then be easily calculated:

C = 2*pi*r
53.38 = 2*3.14*r
53.38 = 6.28r
r = 53.38/6.28
r = 8.5 ft

Thus, the radius of the circle has a length of 8.5 feet.
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Expand and simplify (x + 3)(x-4)
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Answer: x^2x-12 (by the way ^2 is a square)
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What mathematical operation do you use to solve to waist to hip ratio
scoray [572]
Divition is the answer 
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5 0
3 years ago
Ella has gold,silver,and copper wire for stringing beads.she has1 1\2ft.of gold wire,2 1\3ft.of silver wire,and3 3\4ft.of copper
Oksana_A [137]
Ella would have 65/8ft wire all together.
3 0
3 years ago
PLEASE HELP I WILL GIVE A LOT OF POINTS!
vazorg [7]

9514 1404 393

Answer:

  (2.27, 0.96)

Step-by-step explanation:

The orthocenter is the point of intersection of altitudes of the triangle. The equation for an altitude is the equation of a line through a vertex that is perpendicular to the opposite side.

For example, the line perpendicular to side AC can be found as ...

  (∆x, ∆y) = C-A = (3, -1) -(-4, 2) = (7, -3)

  ∆x(x -h) +∆y(y -k) = 0 . . . . perpendicular through point (h, k)

For side AC, we want the point to be B(4, 5), so the equation is ...

  7(x -4) -3(y -5) = 0

  7x -3y -13 = 0

Similarly, the altitude to side AB can be written as ...

  (∆x, ∆y) = B -A = (4, 5) -(-4, 2) = (8, 3)

  8(x -3) +3(y +1) = 0

  8x +3y -21 = 0

__

By the "cross multiplication method", the solution to these equations is ...

  x = (-3(-21) -(3(-13))/(7(3) -8(-3)) = (63+39)/(21+24) = 102/45 = 2 4/15 ≈ 2.27

  y = (-13(8) -(-21)(7))/45 = 43/45 ≈ 0.96

The orthocenter is near (2.27, 0.96).

__

A graphing application confirms this result.

_____

<em>Additional information about the cross multiplication method</em>

For the general form equations ...

  • ax +by +c = 0
  • dx +ey +g = 0

The "cross multiplication method" has you write the array ...

  \begin{array}{cccc}a&b&c&a\\d&e&g&d\end{array}

and form the "cross products" in groups of four coefficients:

  D = ae -db, X = bg -ec, Y = cd -ga

Then the solution to the set of equations is ...

  1/D = x/X = y/Y   ⇒   x = X/D, y = Y/D

__

<em>Additional note</em>

Videos of this method show you writing the array as bcab/egde and using the final equation x/X=y/Y=1/D. The above gets the same result in a more straightforward manner.

3 0
2 years ago
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