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Klio2033 [76]
3 years ago
8

What is the slope of a line that is perpendicular to the line y = 8x + 5?

Mathematics
2 answers:
sergey [27]3 years ago
8 0
<span>perpendicular lines, slope is opposite and reciprocal
</span><span>y = 8x + 5 has slope = 8
so </span><span>perpendicular line slope = -1/8

answer
-1/8</span>
valentina_108 [34]3 years ago
5 0

Answer: \dfrac{1}{8}

Step-by-step explanation:

The given equation of a line : y = 8x + 5

We know that general Slope-intercept form of equation is given by :-

y=mx+c, where m is the slope of the line.

When we compare the given equation the general slope intercept form of equation , we get

Slope of line = 8

We know that the product of slopes of two perpendicular line is -1.

Let m be the slope of  line that is perpendicular to the line y = 8x + 5, then we have

-8\times m=-1\\\\\Rightarrow\ m=\dfrac{1}{8}

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If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

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Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

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So we can say that

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Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

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3 years ago
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Answer:

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1. Organize it, variables first - as well as adding constants such as 4 and -7

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3. Simplify

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