What is the slope of a line that is perpendicular to the line y = 8x + 5?

2 answers:

8 0

<span>perpendicular lines, slope is opposite and reciprocal
</span><span>y = 8x + 5 has slope = 8
so </span><span>perpendicular line slope = -1/8

answer
-1/8</span>

valentina_108 [34]3 years ago

5 0

Answer: $\dfrac{1}{8}$

Step-by-step explanation:

The given equation of a line : $y = 8x + 5$

We know that general Slope-intercept form of equation is given by :-

$y=mx+c$ , where m is the slope of the line.

When we compare the given equation the general slope intercept form of equation , we get

Slope of line = 8

We know that the product of slopes of two perpendicular line is -1.

Let m be the slope of line that is perpendicular to the line $y = 8x + 5$ , then we have

$-8\times m=-1\\\\\Rightarrow\ m=\dfrac{1}{8}$

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Step-by-step explanation:

how confusingly described.

let me try and summarize what I understood :

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