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NARA [144]
3 years ago
7

If angle a = 15 degrees, what does angle b equal

Mathematics
2 answers:
vlabodo [156]3 years ago
6 0

Answer:

75 degrees.

Step-by-step explanation:

Both angles are complementary angles.

They add up to 90 degrees.

90 - 15 = 75

Rzqust [24]3 years ago
6 0

Answer:

90=b+a

90=b+15

Therefore

90-15=b

B=75 degrees

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To make hummingbird nectar you must use 4 cups of water and 1 cup of sugar. What is the ratio of water to sugar?
Reika [66]
The ratio of water to sugar would be 4:1 or 4 to 1.

Hope this helps!

Can u plz mark me as brainliest? I really need it!
6 0
3 years ago
Which inequality has a dashed boundary line when graphed? A y>=3/5x+1 B y>= -1/3x+1 C y>3x+1
Ket [755]

Answer: C y>3x+1

Step-by-step explanation:

  • When we graph an  inequality with strictly greater of less than sign ('<' or '>'), then the graph has a dashed boundary line .
  • Further it indicates that it does not include the points on the line.

From all the given options , only C contains inequality with '>' sign .

Hence, y>3x+1 is the inequality has a dashed boundary line when graphed.

hence, the correct option is C.

4 0
2 years ago
A-attached earlobes a-unattached earlobes if a is the allele for having attached earlobes, what percentage of offspring will hav
Scorpion4ik [409]

The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.

What is a Dominant Trait?

A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.

Given the following traits:

A - attached earlobes (dominant allele)

a - unattached earlobes (recessive allele)

A cross between Aa and aa is shown in the image attached below.

The offspring having attached earlobes = 2 Aa = 50%.

50% of the osspring will have attached earlobes.

Learn more about dominant trait on:

brainly.com/question/16616523

4 0
1 year ago
A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,
algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}

Where v_i is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is [0, \pi/2]. The critical  points of the function are those who make d'(\theta)=0:

d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}

d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...

The critical value inside the interval is \pi/4.

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft

The second step is to find the values of the function at the endpoints of the interval:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft

The biggest value of f is gived by \pi/4, therefore \pi/4 is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

4 0
3 years ago
Help will mark brainiest!
Darya [45]

Answer:

Sry Im guessing. You divide the actual length of pole by the shadow then multiply it to shadow of the tower...

Step-by-step explanation:

Hope it helps

6 0
2 years ago
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