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3 years ago

PLEASE HELP ASAP!!!!!

Mathematics

2 answers:

Lostsunrise [7]3 years ago

5 0

Answer:A(1,1),B(-2,-1),C(-4,0) and I need to draw the slope of the points to make it a triangle.Hope this will help.The red line is y=-x.

padilas [110]3 years ago

3 0

Answer:

A'''(1,1), B'''(-2,-1) and C'''(-4,0).

Step-by-step explanation:

Triangle ABC has vertices with coordinates A(-6,-1), B(-3,-3) and C(-1,-2) (from given diagram).

1. Translation the triangle ABC 5 units to the right and 2 units up has a rule

(x,y)→(x+5,y+2).

Then the image triangle A'B'C' has vertices A'(-1,1), B'(2,-1) and C'(4,0).

2. Reflection the triangle A'B'C' across the line y=-x has a rule

(x,y)→(-y,-x).

Then the image triangle A"B"C" has vertices A"(-1,1) (this point lie on the line), B"(1,-2) and C"(0,-4).

3. Rotation the triangle A"B"C" counterclockwise about the origin by 270° has a rule

(x,y)→(y,-x).

Then the image triangle A'''B'''C''' has vertices A'''(1,1), B'''(-2,-1) and C'''(-4,0).

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I WILL GIVE 20 POINTS PLEASE HELP

tensa zangetsu [6.8K]

Answer:

71 and 72

Step-by-step explanation:

a+b=8

cd id divisible by 8.

ab=17,26,35,44,53,62,71

The only number above with a consecutive number of 8 is 71. (71 and 72)

5 0

3 years ago

Read 2 more answers

Assume that a procedure yields a geometric distribution where the probability of success is 19%. Use the geometric probability f

Rudiy27

The probability that the first success occurs on the third trial is 0.125.

Answer: Option C

<u>Step-by-step explanation:</u>

The probability of success is given by the geometric distribution formula:

$P(X=x)=p \times q^{x-1}$

Where,

p = probability of success for single trial.

q = probability of failure for a single trial (1-p)

x = the number of failures before a success.

P(X = x) = Probability of x successes in n trials.

<u>Given: </u>

p = 19% = 0.19

q = 1 – p = 1 – 0.19 = 0.81

x = 3

We want to find the probability that the first success occurs on the third trial so,

$P(X=3)=0.19 \times 0.81^{(3-1)}$

$P(X=3)=0.19 \times 0.81^{2}$

$P(X=3)=0.19 \times 0.6561=0.125$

5 0

4 years ago

deb and luke go to the pi-rate entertainment store to purchase cds (c) and dvds (d). deb buys 3 dvds and 2 cds for $63 (before s

Leokris [45]

We are given here the individual costs of DVD and CD as well as the total sales and the number of items sold on one day. To solve the number of DVDs and CDs sold each, we devise two independent linear equations:

(1) x + y = 39

(2) 4x + 7y = 204

x- number of DVDs; y - number of CDs

solving, x= 23 DVDs

4 0

3 years ago

Read 2 more answers

What is the midpoint of a line segment with endpoints at (3,-2) and (1,7)? A. (2,-9/2) B. (2,-5/2) C. (2,5/2) D. (2,9/2)

Ulleksa [173]

The Midpoints of the line segment is (2, 5/2)

Step-by-step explanation:

The line is defined by starting and ending coordinates.

As given in the question starting coordinates are given as (3,-2) and the ending coordinates are provided as (1,7)

The midpoint of the life segment-

The midpoint of the line can be found by individually finding of each “x” and “y” coordinate from both ends.

Thus, x coordinate of the midpoint is (3+1)/2= 2

Similarly, the Y coordinate of the midpoint is (-2+7)/2 = 5/2

Hence the Midpoint of the life segment- (2, 5/2)

7 0

3 years ago

9. Calcule el valor de la fuerza que experimenta un ascensor cuando levanta 150 kg en los siguientes casos: a) Cuando asciende c

GenaCL600 [577]

Answer:

a) La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) Por la fuerza de tensión sobre el cable del ascensor.

Step-by-step explanation:

a) La fuerza neta experimentada por el ascensor ( $F$ ), en newtons, es:

$F = m\cdot a$ (1)

Donde:

$m$ - Masa, en kilogramos.

$a$ - Aceleración, en metros por segundo cuadrado.

Si sabemos que $m = 150\,kg$ y $a = 4\,\frac{m}{s^{2}}$ , entonces la fuerza neta del ascensor es:

$F = m\cdot a$

$F = 600\,N$

La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) Si sabemos que $m = 150\,kg$ y $a = -6\,\frac{m}{s^{2}}$ , entonces la fuerza neta del ascensor es:

$F = m\cdot a$

$F = -900\,N$

La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) De manera simplificada, el ascensor experimenta dos fuerzas que definen la fuerza y aceleración netas: (i) La fuerza de tensión sobre el cable que traslada el ascensor y el peso total del ascensor, opuesta a la anterior y en función de la aceleración gravitacional. Puesto que la masa no varía en ningún caso, se concluye que el peso es constante, entonces la diferencia de valores se debe a la fuerza por tensión del cable. En el descenso, es fuerza es menor que en el ascenso.

8 0

3 years ago