Answer:
Option C (f(x) = 
)
Step-by-step explanation:
In this question, the first step is to write the general form of the quadratic equation, which is f(x) = 
, where a, b, and c are the arbitrary constants. There are certain characteristics of the values of a, b, and c which determine the nature of the function. If a is a positive coefficient (i.e. if a>0), then the quadratic function is a minimizing function. On the other hand, a is negative (i.e. if a<0), then the quadratic function is a maximizing function. Since the latter condition is required, therefore, the first option (f(x) = 
) and the last option (f(x) = 
) are incorrect. The features of the values of b are irrelevant in this question, so that will not be discussed here. The value of c is actually the y-intercept of the quadratic equation. Since the y-intercept is 4, the correct choice for this question will be Option C (f(x) = ). In short, Option C fulfills both the criteria of the function which has a maximum and a y-intercept of 4!!!
