Answer:
Choice 1
Step-by-step explanation:
Let‘s go through each answer and analyze a
each.
<u><em>Choice 1</em></u>
<u>Parallel</u> means to lines with the same slope, they never intersect, ever, they always remain next to each other and never touch. This is true for the picture
<u><em>Choice 2</em></u>
<u>Perpendicular</u> means that two lines intersect at a right angle, however upon looking at the picture you can see this is not a right angle, but an acute angle. So it is not perpendicular.
<u><em>Choice 3</em></u>
A <u>Line Segment </u>means a line with dots on either end, symbolizing the end of the line. This is not a line segment because there are arrows on the ends, indicating these lines go on forever. This is not a segment
<u><em>Choice 4</em></u>
We already determined this is neither a segment nor perpendicular so it cannot be this choice
This leaves us with Choice 1.
I hope this helps!
Please give thanks and brainliest!
Answer:
<h2>The solution is -9 < x < 17.</h2>
Step-by-step explanation:
|x-4|<13.
The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.
Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.
Answer:
The intercepts are the locations where the line touches the x-axis and y-axis.
This question is asking for the coordinates for each of those locations, which would be:
(3, 0) for x-intercept location
(0, -10) for y-intercept location
The easy way to remember how to find coordinates is that the x is 'running', and the y is 'jumping', so the x coordinate comes before the y coordinate when finding sets like the ones above.
X^2 + 2xy + -x + y^2 + -y + -12
Answer:
Step-by-step explanation:
Adjacent angles of parallelogram are supplementary.
∠A + ∠D = 180
Divide both sides by 2
∠A + ∠D = 90
∠PAD + ∠ADP = 90 --------------------(I)
IN ΔPAD,
∠PAD + ∠ADP + ∠APD = 180 {angle sum property of triangle}
90 + ∠APD = 180 {from (I)}
∠APD = 180 - 90
∠APD = 90
∠SPQ = ∠APD {vertically opposite angles}
∠SPQ = 90°
Similarly, we can prove ∠PQR = 90° ; ∠QRS = 90° and ∠RSP = 90°
In a quadrilateral if each angle is 90°, then it is a rectangle.
PQRS is a rectangle.
