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Sati [7]
3 years ago
14

Find the suface area of this trangular prism.

Mathematics
1 answer:
Talja [164]3 years ago
5 0
The answer will be 37 yd. Hope it help!
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The cost table shows the average cost, a(x), of
erastovalidia [21]

Reverse the numbers in the table to get:

(52,20) (67.5,25) and (64,30)

The answer would be (52,20)

7 0
2 years ago
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PLEASE HELP SOLVE THIS!!!!!!!!!!!
Sphinxa [80]

9514 1404 393

Answer:

  a) yes; 12/15/17 ~ 20/25/x; SAS

  b) x = 28 1/3

Step-by-step explanation:

The left-side segments are in the ratio ...

  top : bottom = 12 : 8 = 3 : 2

The right side segments are in the ratio ...

  top : bottom = 15 : 10 = 3 : 2

These are the same ratio, and the angle at the peak is the same in both triangles, so the triangles are similar by the SAS postulate.

Normally, a similarity statement would identify the triangles by the labels on their vertices. Here, there are no such labels, so we choose to write the statement in terms of the side lengths, shortest to longest:

  12/15/17 ~ 20/25/x

__

The sides of similar triangles are proportional, so the ratio of longest to shortest sides will be the same in the two triangles. In the smaller triangle, the longest side is 17/12 times the length of the shortest side. The value of x will be 17/12 times the length of the shortest side in the larger triangle:

  x = 17/12 · 20 = 340/12

  x = 28 1/3

4 0
3 years ago
Can yall check my answer ?
Rzqust [24]

Answer:

its good :)

Step-by-step explanation:

6 0
3 years ago
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A weightlifter holds a 1,700 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the ba
masha68 [24]
In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.

W = Fd

The total force is 
F = 1,700 N + 500 N = 2,200 N
Now, if the question is the work needed to lift the barbell from the ground, the distance would be 2 m. Hence, the work would be

W = (2,220 N)(2 m) = 4,400 N·m or 4,400 J
5 0
3 years ago
gretchen and henrik are meeting at a park. gretchen lives 2.4 miles away from the park and bikes at a constant rate of 12 miles
shepuryov [24]
1)t=S/U=2.4/12=0.2
2)t=S/U=8.4/36=0,23
3)0.23-0.2=0.03




6 0
3 years ago
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