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Sati [7]
3 years ago
14

Find the suface area of this trangular prism.

Mathematics
1 answer:
Talja [164]3 years ago
5 0
The answer will be 37 yd. Hope it help!
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Please help it's due today haha:/
Ludmilka [50]

Answer:

C

Step-by-step explanation:

The pool raises 30 inches every 4 secounds

Therefore the equations to find the answer is 30 divided by 4 which equals 7.5

4 0
3 years ago
Read 2 more answers
What is the solution to 7 • p = –56? a. p = –49 b. p = –8 c. p = 8 d. p = 49
Lostsunrise [7]
The correct answer is p=-8
8 0
3 years ago
A jet files at an altitude of 52,800 feet. what is the height of the hey on miles
Triss [41]
There are 5,280 feet in a mile. so 52,800 feet is 10 miles.
4 0
3 years ago
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Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
Simplify 24 – 6x – 18 + 5x<br><br> 3 – 3x<br><br> –x + 6<br><br> 2x – 3<br><br> –4x – 17
Svetach [21]

= <span><span>−x</span>+6</span>

<span>=<span><span> −<span>3x</span></span>+3</span></span>

<span>= </span><span><span>−x</span>+6</span>
= <span><span>2x</span>−3</span>

<span>= <span><span>−<span>4x</span></span>−<span>17</span></span></span>


6 0
3 years ago
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